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guapka [62]
3 years ago
5

What is the value of x in the figure? Enter your answer in the box.

Mathematics
2 answers:
irina [24]3 years ago
7 0

Answer:

the answer is 29° because you have to subtract 61 from 90 and you will  get 29.

x = 29°

Gekata [30.6K]3 years ago
4 0

Answer:

The answer is 29°

Step-by-step explanation:

We are given a figure,

Here, we know that on straight line the sum of all angles is equal to 180°

So,

x + 90° + 61° = 180°

x + 151° = 180°

x = 151° – 151° = 180° – 151°

x = 29°

Thus, The value of x is 29°

<h3><u>For </u><u>Verification</u>;</h3>

x + 90° + 61° = 180°

29° + 90° + 61° = 180°

180° = 180°

L.H.S = R.H.S

Hence Verified!

<u>-TheUnknownScientist 72</u>

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Zach is trying to decide which of three golf
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Answer:

No, the population of people is poorly represented with this low sample size. 150 would better represent the population as a whole. 42 people would want to play on Rolling Meadows. (according to the previous data)

Step-by-step explanation:

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Jean throws a ball with an initial velocity of 64 feet per second from a height of 3 feet. Write an equation and answer the ques
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<h2>a. What is your equation?</h2>

This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:

h(t)=-\frac{1}{2}gt^2+v_{0}t+h_{0}

Where:

h(t): \ height \ at \ any \ time \\ \\ g: \ acceleration \ due \ to \ gravity \ 9.8m/s^2 \ or \ 32.16ft/s^2 \\ \\ v_{0}= \ Initial \ velocity

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v_{0}=64ft/s \\ \\ h_{0}=3ft

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h(t)=-\frac{1}{2}(32.16)t^2+(64)t+3 \\ \\ \boxed{h(t)=-16.08t^2+64t+3}

<h2>b. How long will it take the rocket to reach its maximum height?</h2>

The rocket will reach the maximum height at the vertex of the parabola described by the equation h(t)=-16.08t^2+64t+3. Therefore, our goal is to find t at this point. In math, a parabola is described by the quadratic function:

f(x)=ax^2+bx+c

So the x-coordinate of the vertex can be calculated as:

x=-\frac{b}{2a}

From our equation:

a=-16.08 \\ \\ b=64 \\ \\ c=3

So:

t=-\frac{64}{2(-16.08)} \\ \\ \boxed{t=1.99s}

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From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by h(1.99). Thus, we can find this as follows:

H_{max}=h(1.99)=-16.08(1.99)^2+64(1.99)+3 \\ \\ \boxed{H_{max}=66.68ft}

So the maximum height the rocket will reach is 66.68ft

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We can't have negative value of time, so the only correct option is t_{1}=4.0264 and rounding to the nearest hundredth we have definitively:

\boxed{t=4.03s}

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