Ask question

Ask question

All categories

3 years ago

12

a pizza restaurant offers the following deals deal number one eight $99 for a large pizza and $5 each for additional large pizza

on the same order deal number to $6 per large pizza at what number of pizzas does steel number one become a better deal what is the cost of the Tempe classes for HDL what is the cost per Pizza in the old number one which is the better deal and why

2 answers:

lozanna [386]3 years ago

8 0

Answer:

At 4th pizza , Deal 1 will be better than Deal 2
At Deal 1 the cost of 10 pizzas is 53,99, and at deal 2 the cost of 10 pizzas is 60.
If you purchase 10 pizzas , the cost of each pizza is $5,39 in deal 1 , in deal 2 the cost is always $6
To determinate the better deal you have to determinate the quantity you want to purchase.

Step-by-step explanation:

File is attached with the calculus of deal 1 and deal 2.

Quantity Deal 1 Deal 2

1 8,99 6

2 13,99 12

3 18,99 18

4 23,99 24

5 28,99 30

6 33,99 36

7 38,99 42

8 43,99 48

9 48,99 54

10 53,99 60

mote1985 [20]3 years ago

6 0

Answer:

108

Step-by-step explanation:

You might be interested in

2072 divided by 37! Pleaseeeeeeeeee

icang [17]

Answer:

56 is the answer to your question

6 0

2 years ago

Read 2 more answers

What set of transformations is performed on triangle RST to form triangle R’S’T’?

ra1l [238]

Answer:

D. A translation 2 units down followed by a 270-degree counterclockwise rotation about the origin

Step-by-step explanation:

The given triangle has vertices at R(3,4), S(1,1), and T(5,1)

Translating the the vertices down by 2 units, we apply the rule;

$(x,y)\to (x,y-2)$

$\implies (3,4)\to (3,2)$

$\implies (1,1)\to (1,-1)$

$\implies (5,1)\to (5,-1)$

Rotating the resulting vertices through an angle 270 degrees counterclockwise, we apply the rule:

$(x,y)\to (x,-y)$

$\implies (3,2)\to R'(2,-3)$

$\implies (1,-1)\to S'(-1,-1)$

$\implies (5,-1)\to T'(-1,-5)$

Therefore the correct choice is D.

4 0

3 years ago

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

<u>For urn 2</u>

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

2 years ago

At the banquet 450 people had chicken and 150 had pasta. What percent of people has pasta?

Liono4ka [1.6K]

25 percent of people had pasta.

First add 450 and 150 (which equals 600)

Next divide 600 by 150 (which equals 4)

Which means 150 is a fourth of six hundred, and a fourth is 25 percent.

Which leads to my answer of 25 percent

5 0

2 years ago

The scale of a map is 1:4 000 000. Hint: 1:4 000 000 means that 1cm on the map = 4 000 000 on the ground. The distance between L

GrogVix [38]

Answer:

325 km

Step-by-step explanation:

Given the scale :

1 : 4 ,000, 000

1cm measure in map = 4000000 on the ground

From the map :

Distance between Leeds and London = 8.125 cm

The actual distance on ground can be calculated thus :

1cm = 4,000,000

8.125cm = x

Cross multiply

x = 32500000 cm

Converting to kilometers :

1 km = 100,000 cm

x = 32500000

Cross multiply

100,000x = 32500000

x = 32500000 / 100000

x = 325

Hence, actual distance between Leeds and London is 325 km

3 0

2 years ago