Answer:
x = 12
Step-by-step explanation:
Recall: the secant-tangent rule states that when a secant and a tangent meet at an external point of a circle, the product of the secant and the external segment is equal to the square of the tangent segment
(x)(3) = 6² (secant-tangent rule)
3x = 36
Divide both sides by 3
3x/3 = 36/3
x = 12
Answer:
v = ± sqrt(6/5)
Step-by-step explanation:
v^2+2=8-4v^2
Add 4v^2 to each side
v^2+ 4v^2+2=8-4v^2+ 4v^2
5v^2 +2 = 8
Subtract 2 from each side
5v^2 +2-2 = 8-2
5 v^2 = 6
Divide each side by 5
5v^2 /5 = 6/5
v^2 = 6/5
Take the square root of each side
sqrt(v^2) = ± sqrt(6/5)
v = ± sqrt(6/5)
8xy-7xy-3xy-3y²-2y²+8y²+5x²+12x²
then simplify by combining like terms -2xy+3y²+17x²
Answer:
The sum of the first 6 terms is 3,412.5.
Step-by-step explanation:
The second term of the geometric series is given by:
Where a1 is the first term and r is the common ratio. The seventh term can be written as a function of the second term as follows:
![a_{7}=a_{1}*r^{6} \\a_{7}=a_{2}*r^{5} \\10,240 = 10*r^{5}\\r=\sqrt[5]{1024} \\r = 4](https://tex.z-dn.net/?f=a_%7B7%7D%3Da_%7B1%7D%2Ar%5E%7B6%7D%20%5C%5Ca_%7B7%7D%3Da_%7B2%7D%2Ar%5E%7B5%7D%20%5C%5C10%2C240%20%3D%2010%2Ar%5E%7B5%7D%5C%5Cr%3D%5Csqrt%5B5%5D%7B1024%7D%20%5C%5Cr%20%3D%204)
The sum of "n" terms of a geometric series is given by:
The sum of the first 6 terms is 3,412.5.
