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leva [86]
3 years ago
5

Question 8 Which graph shows a linear function​

Mathematics
2 answers:
krok68 [10]3 years ago
8 0
The top left shows a linear function
Andreas93 [3]3 years ago
3 0
One one of the top and to the right because it is a straight line so it has a constant slope and is in y=Mx+b form
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Simplify the expression 1/2(x-10) - 3
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(b) The table below indicates the cost of certain air tel kiosk Z 0.15 0.20 0.25 0.75 0.80 0.85 1.85 1.90 1.95 2.00 2.05 QZ 0.05
marshall27 [118]

Using the normal distribution, it is found that there is a

a) 0% probability that the number of calls received at the switchboard will be exactly 578.

b) 0.1586 = 15.86% probability that the number of calls received at the switchboard will be less than 570.

c) 0.9485 = 94.85% probability that the number of calls received at the switchboard will be between 561 and 600.

<h3>Normal Probability Distribution</h3>

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 580, hence \mu = 580.
  • The standard deviation is of 10, hence \sigma = 10.

Item a:

In the normal distribution, the probability of an exact value is 0%, hence, 0% probability that the number of calls received at the switchboard will be exactly 578.

Item b:

The probability is the <u>p-value of Z when X = 570</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{570 - 580}{10}

Z = -1

Z = -1 has a p-value of 0.1586.

0.1586 = 15.86% probability that the number of calls received at the switchboard will be less than 570.

Item c:

This probability is the <u>p-value of Z when X = 600 subtracted by the p-value of Z when X = 561</u>, hence:

X = 600:

Z = \frac{X - \mu}{\sigma}

Z = \frac{570 - 580}{10}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 561:

Z = \frac{X - \mu}{\sigma}

Z = \frac{561 - 580}{10}

Z = -1.9

Z = -1.9 has a p-value of 0.0287.

0.9772 - 0.0287 = 0.9485.

0.9485 = 94.85% probability that the number of calls received at the switchboard will be between 561 and 600.

You can learn more about the normal distribution at brainly.com/question/24663213

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