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Serhud [2]
2 years ago
10

Can someone please give me the (Answers) to this? ... please ... I need help….

Mathematics
1 answer:
Brums [2.3K]2 years ago
6 0

Answer:

see below

Step-by-step explanation:

I will be using pythagorean triples for some, but you can use sqrt(a^2+b^2)=c^2

1. 12 13 5 x=5

2. 3 4 5 x=5

3. sqrt(14.7^2-11.9^2)=sqrt(74.48) or around 9 (root is irrational)

4. sqrt(15.4^2-6.3^2)=sqrt(197.47) or around 14 (same thing)

5. sqrt(15^2-11^2)=2*sqrt(26) or around 10

6. sqrt(4^2-sqrt(6)^2)=sqrt(16-6)=sqrt(10) or around 3

7. sqrt(12^2+9^2)= 15, so it is a right triangle

8. 9, 12, 15 divide by 3- 3, 4, 5 pythagorean triple - is a right triangle

9. 9, 12, 15-17>15, obtuse

10. sqrt(20.1^2+18^2)=20.4 - 20.1<20.4, acute

11. sqrt(4.8^2+28.6^2)=29, 29=29, right

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