Answer:
the answer is c beucse yses
Step-by-step explanation:
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
Answer:
y=40-15x
Step-by-step explanation:
Let x represent the number of hours.
We have been given that Dudley travels 30 miles every 2 hours, so distance covered in each hour by Dudley would be:
.
Since Dudley travels 15 km per hour, so distance covered in x hours would be 15x.
We have been given that Dudley wants to cover 40 miles. So we can represent our given information in an equation as:
, where, y represents number of miles he has left to travel, after biking x hours.
If you would like to write and solve a system of equations that represent the situation above, you can do this using the following steps:
s ... number of songs
m ... number of movies
$55.00 = $1.25 * s + $2.75 * m
55 = 1.25 * s + 2.75 * m
26 songs and movies = s + m
26 = s + m
s = 26 - m
55 = 1.25 * s + 2.75 * m
55 = 1.25 * (26 - m) + 2.75 * m
55 = 1.25 * 26 - 1.25 * m + 2.75 * m
55 - 32.5 = 1.5 * m
22.5 = 1.5 * m
m = 22.5 / 1.5 = 15 movies
s = 26 - m = 26 - 15 = 11 songs
The correct result would be 15 movies and 11 songs.
The scenario that matches with the linear relationship shown in the table is option 2:
"Shanna had $ 10 in her piggy bank and earned $ 5 each week in allowance"
You could see that I had $ 10 initially in week zero and every two weeks I had $ 10 more. Therefore it can be inferred that every two weeks has won $ 10, that is, $ 5 each week
