Answer:
(2, 7)
Step-by-step explanation:
represents the reflection of a point P about the y-axis.
If a point (x, y) is reflected across y-axis, rule for the reflection is,
(x, y) → (-x, y)
If a point (-2, 7) follows the same rule, coordinates of the image point will be,
P(-2, 7) → P'(2, 7)
Therefore, answer is (2, 7).
Answer:
The statement is true
Step-by-step explanation:
The question is as following :
is divisible by 7 and 19, true or false?
The given expression is 
Take
as a common

So,
divided 7 = 
And
divided 19 = 
is divisible by 7 and 19 (<u>True</u>)
A. True. We see this by taking the highest order term in each factor:

B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.
C. False. f(x) = 0 only for x=0, x = 5, and x = -2.
D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.
E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).
F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.
Answer:
50000 times
Step-by-step explanation:
Since these are given in scientific notation, we can convert them to have the same powers of 10. Converting 4*10^12 to something times 10^7, we can get 4*10^5*10^7. So we divide 400000 by 8 to see how many times larger it is than 8. So we get 50000 times as our answer.
<h3>
Answer: Choice A. |w - q|</h3>
Let's say for example that w = 10 and q = 7. This means the distance between these values is w-q = 10-7 = 3. This is the distance between w and q.
Now let's make q larger. If w = 12 and q = 20, then w-q = 12-20 = -8 assuming we subtract in the same order. We use absolute value bars to ensure the result is positive. So instead we say
|w - q| = |12 - 20| = | -8 | = 8
Distance is never negative.