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NemiM [27]
2 years ago
12

For a one-sample test for a population proportion p and sample size n, why is it necessary that np0 and n(1−p0) are both at leas

t 10 ?.
Mathematics
1 answer:
tino4ka555 [31]2 years ago
6 0

Using the Central Limit Theorem, it is found that these conditions are required to avoid the high variability associated with small samples.

<h3>What does the Central Limit Theorem states?</h3>

It states that for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

From the equation of the standard error, we could see that if one of the conditions is not respected, the standard error would be very high, indicating a low accuracy of the estimate, hence it is found that these conditions are required to avoid the high variability associated with small samples.

More can be learned about the Central Limit Theorem at brainly.com/question/24663213

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A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

5 0
3 years ago
A small company 's net income for the first 6 months of the year was 76.500 and for the last six months it was 100,000 . What is
inna [77]

Answer:The ratio of net income in the first 6 months, to the last six months is $76,500 / $100,000. This simplifies intuitively as follows:

76500/100000

Dividing by 100: 765/1000

Dividing by 5: 153/200

The denominator 200 is only divisible by the prime numbers 2 and 5, and since the numerator 153 is not divisible by either 2 or 5, this means that this is in simplest form, and the final answer is 153/200.

Step-by-step explanation:i did the research for you this isnt my own answer therefore don't give me the credit. but hope this helped you tho :D

5 0
3 years ago
Jonathan bought a table and some chairs at a furniture store.
Naily [24]

Answer:

It must be the cost of the one table.

Step-by-step explanation:

It's logic. 25x is the cost of the (unknown) number of chairs.

The total Amount he spent is the cost of the chairs <u>plus</u> what he spent on the table.

4 0
3 years ago
In Mark's collections, the ratio of basketball cards to football cards is 7 to 4.
cestrela7 [59]
The answer is 11 sorry if I’m wrong
3 0
2 years ago
Read 2 more answers
The area of a rectangular pool is (15x-9) square
ch4aika [34]
Ok so find greatert common factor
ab+ac=a(b+c)

15x=3*5*x
9=3*3
gcf=3

15x-9=
3(5x)+3(-3)=
3(5x-3)

possible dimentions is 3 unit and 5x-3 units
3 0
3 years ago
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