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Diano4ka-milaya [45]
2 years ago
12

Find m∠R. please hurry for 50 points!!!

Mathematics
2 answers:
Vikentia [17]2 years ago
7 0

Answer:

124

Step-by-step explanation:

The sum of interior angles in a triangle is equal to 180:

m<R + m<S + m<T = 180

11x + 3 + x + 15 + 2x + 8 = 180 add like terms

14x + 26 = 180 subtract 26 from both sides

14x = 154 divide both sides by 14

x = 11 to find m<R replace x with 11

11*11 + 3 = 124

VikaD [51]2 years ago
7 0

Apply angle sum property

\\ \rm\rightarrowtail 11x+3+x+15+2x+8=180

\\ \rm\rightarrowtail 14x+26=180

\\ \rm\rightarrowtail 14x=154

\\ \rm\rightarrowtail x=11

  • m<R=11(11)+3=124
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Answer:

Fast train speed: 69 km/h

Slow train speed: 39 km/h

Step-by-step explanation:

Fast train:

-Time: 4.33

-Speed: x

-Distance: 4.33x

Slow train:

-Time:  7.66

-Speed: x - 30

-Distance: 7.66(x - 30)

7.66(x - 30) = 4.33x

7.66x - 229.8 = 4.33x

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x = 69

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2 years ago
Find the quotient. If possible, rename the quotient as a mixed number or a whole number. Write your answer in simplest form, 2 1
anyanavicka [17]

Answer:

1 26/49

Step-by-step explanation=

2 1/7 ÷ 1 2/5

15/7 over 1 2/5

15/7 over 7/5  

75/49  

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5 0
2 years ago
You are w rapping the boxed DVD collection as a present. What is
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7 0
2 years ago
3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third
den301095 [7]

Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

2x + 3(x + 2) = 2(x + 4) + 55

=  > 2x + 3x + 6 = 2x + 8 + 55

Eliminating 2x from both the sides,

=  > 3x + 6 = 63

=  > 3x = 63 - 6 = 57

=  > x =  \frac{57}{3}  = 19

So, the consecutive odd integers are = 19 , 21 & 23.

3 0
2 years ago
What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0
Free_Kalibri [48]

Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, option B is true.

6 0
3 years ago
Read 2 more answers
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