It's C they are just out of order for the years.
f(x)=35.5x+6
For each year your plug in the snow total for x and solve
2006 x=53 so 35.5(53)+6=1887.5
2007 x=42 so 35.5(42)+6=1497
2008 x=55 so 35.5(55)+6=1958.5
2009 x=63 so 35.5(63)+6=2242.5
2010 x=58 so 35.5(58)+6=2065
2011 x=47 so 35.5(47)+6=1674.5
Hope that helps.
Answer:
sln
f(x) =-22+x+14 put 2 in x
f(2)=-22+2+14
f(2) =38
9514 1404 393
Answer:
4/5 acre
Step-by-step explanation:
We assume your allocations are ...
goats: 3/5 acre
pigs: 1/5 acre
llamas: 2/5 acre
2 acres is 10/5 acres, so the remaining area is ...
10/5 -3/5 -1/5 -2/5 = (10 -3 -1 -2)/5 = 4/5
4/5 acre is allocated to horses.