Area of a circle for (360degrees) = pi*(r^2)
Area of part of a circle with angle θ=(θ/360)*(pi*)*(r^2)
<span>(θ/360)*pi*(6^2)=12*pi
</span>solving, <span>θ=(12/36)*360
</span><span>θ=120 degress
</span>
Difference Of Two Squares
<span>a^2 - b^2 = a^2 - b^2
</span><span>so
x^2-64
=x^2 - 8^2
= (x + 8)(x - 8)</span>
Answer:
Step-by-step explanation:
Only one of them has a < b in ax² + by² = c formula, making its graph horizontal
All the rest are vertical, see attached
For the first one, I will solve for t.
s + 2t = 6, first we isolate the t variable,
2t = -s + 6, divide both sides by 2,
t = -s/2 + 3, < There's your answer for 1!
Here's the second one,
3s - 2t = 2, subtract 3s from both sides,
-2t = 2 - 3s, divide both sides by -2,
t = -1 + 3s/2 < There's your second answer!
The tenths place is right after the decimal point. So, 3160.9903 can be 3160.9.