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frozen [14]
3 years ago
5

A square has a side length of 14 inches. This square is dilated by a scale factor of 35 to create a new square. What is the side

length of the new square?
Mathematics
1 answer:
Harman [31]3 years ago
4 0

The new side length is 8.4. When you do dialations, you multiply the side length, 14, by the scale factor, 3/5. 14 × 3.5 gives you the answer 8.4. Hope this helps!

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Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)
Lorico [155]

Answer:

It is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x .

Step-by-step explanation:

We already have the identity of x as \sin ^{2}x + \cos ^{2}x = 1 .......... (1)  .

So, from equation (1) we can write that

\cos ^{2} x = 1 - \sin ^{2} x

⇒ 6\cos ^{2} x = 6 - 6 \sin ^{2} x

⇒ 6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3

⇒ 6\cos ^{2}x -3 = 3 - 6\sin ^{2} x

Hence, it is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x . (Answer)

5 0
3 years ago
If y = kx, what is the value of k if y = 20 and x = 0.4?<br> A) 5 <br> B) 8 <br> C) 9.6 <br> D) 50
mariarad [96]

Answer:

D) 50

20/0.4=50

Step-by-step explanation:


7 0
2 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
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Aleksandr-060686 [28]

Answer:

497,725

just subtract smallest from largest to get the difference

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4 0
2 years ago
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I know I've asked a bunch of questions but I reallyyyy need help on math
lys-0071 [83]

Answer:

i think its d

8 0
3 years ago
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