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3 years ago

The temperature in frostville was at 50*F at midnight,and it dropped at a constant rate for the next 10 hours.

Mathematics

1 answer:

bazaltina [42]3 years ago

5 0

After 10 hours the temperature is shown on the graph as 30 degrees.

50 degrees - 30 degrees = 20 degrees.

The temperature dropped 20 degrees in 10 hours.

Divide the change by the time:

20 degrees / 10 hours = 2 degrees per hour.

Because the temperature dropped, the change would be negative.

The answer is D. -2 degrees per hour.

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