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In-s [12.5K]
2 years ago
11

PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST​

Mathematics
2 answers:
goblinko [34]2 years ago
5 0

Answer:

C

Answer is
C                                                    

Zepler [3.9K]2 years ago
4 0

Answer:

9.4 ( 4 + 12 ) = 145.6

Step-by-step explanation:

i used a calculator

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.725 , .572 , .275, .2
You look at the first decimal place to see which is the greatest. 7 is greater than 5 and 2 so it's first. Then 5 is greater than 2 so it is next. For the last two numbers since 2 is the same value you look at the next decimal place. Since 7 is greater than 0 it comes next!
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Verb dale had a total of 45.8 inches of rain this year. This year's total was 7.48 inches greater than last year's total. What w
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1. 45.8-7.48=38.32 in

2. 5/6-3/4=10/12-9/12= 1/12 miles farther
5 0
3 years ago
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1. A luge race is very dangerous, and a crash can cause serious injuries. The league requires anyone who has a crash to have a t
antiseptic1488 [7]

Answer:

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

Step-by-step explanation:

For each race, there are only two possible outcomes. Either the person has a crash, or the person does not. The probability of having a crash during a race is independent of whether there was a crash in any other race. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A certain performer has an independent .04 probability of a crash in each race.

This means that p = 0.04

a) What is the probability she will have her first crash within the first 30 races she runs this season

This is:

P(X \geq 1) = 1 - P(X = 0)

When n = 30

We have that:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{30,0}.(0.04)^{0}.(0.96)^{30} = 0.2939

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2939 = 0.7061

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

7 0
3 years ago
Any gírl here<br>.<br>.<br>.<br>.<br>let's chàt​
Rufina [12.5K]

Answer:

uhm no stop this is an app for people and work so please go

3 0
3 years ago
Can you guys help we with this question. ​​​​​​
satela [25.4K]

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

40

4 0
3 years ago
Read 2 more answers
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