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A running track consists of two parallel lines that are connected at each end but the curved boundary of a semicircle. The paral

saveliy_v [14]

Answer:

The area inside the running track is 248.5 m².

Step-by-step explanation:

The area inside the running track is given by the sum of the area of a rectangle and the area of a semicircle:

$A_{t} = A_{r} + 2A_{c}$

$A_{t} = x*(2r) + 2*(\frac{\pi r^{2}}{2})$

Where:

x: is one side of the rectangle = 30 m

r: is the radius = half of the other side of the rectangle = 7/2 m = 3.5 m

Hence, the total area is:

$A_{t} = 30*7 + \pi (3.5)^{2} = 248.5 m^{2}$

Therefore, the area inside the running track is 248.5 m².

I hope it helps you!

3 0

3 years ago

How much should you invest at 4% simple interest in order to earn $50 interest in 6 months

LenaWriter [7]

Simple interest formula
Interest = Pit = $50
P=principal (initial investment)
i=annual interest rate = 0.04
t=time in years = 6 months = 0.5 years

Substitute values,
$50 = P*0.04*0.5
Solve for P
P=$50/(0.04*0.5)=$2500

4 0

2 years ago

Which expression is equivalent to 4 square root 6 divided by 3 root 2

denis-greek [22]

Answer:

The expression is equivalent to 4 square root 6 divided by 3 root 2 is:

8/3

Step-by-step explanation:

Given expression:

4 square root 6 divided by 3 root 2

$\frac{4\sqrt{6}}{3\sqrt{2} }$

$=\frac{4\sqrt{2*2*2}}{3\sqrt{2} }$

$=\frac{4\sqrt{2*2^{2} }}{3\sqrt{2} }$

square root of 2² = 2 hence,

$=\frac{4*2\sqrt{2}}{3\sqrt{2} }$

$=\frac{8\sqrt{2}}{3\sqrt{2} }$

Common terms in the numerator and denominator cancels each other out

$=\frac{8}{3}$

By solving the expression using simple mathematical rules, we got an equivalent expression of

$\frac{4\sqrt{6}}{3\sqrt{2} } = \frac{8}{3}$

7 0

2 years ago

Read 2 more answers

A sample is selected from a population with μ = 46, and a treatment is administered to the sample. After treatment, the sample m

Georgia [21]

Answer:

0.5

Step-by-step explanation:

Solution:-

- The sample mean before treatment, μ1 = 46

- The sample mean after treatment, μ2 = 48

- The sample standard deviation σ = √16 = 4

- For the independent samples T-test, Cohen's d is determined by calculating the mean difference between your two groups, and then dividing the result by the pooled standard deviation.

Cohen's d = $\frac{u2 - u1}{sd_p_o_o_l_e_d}$