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2 years ago

Help other do divide

Mathematics

1 answer:

vovikov84 [41]2 years ago

3 0

Can you say exactly what your asking for.

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10,000-99,999 < 0. true or false

pav-90 [236]

<h2><u>TRUE</u> is the correct answer!</h2><h3 /><h3>10,000 - 99,999 = -89,999</h3><h3>Since it's a NEGATIVE number, it is smaller than zero.</h3><h3 /><h3><em>Please let me know if I am wrong.</em></h3>

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2 years ago

15 points I really need help with this!! And please have work not just the answer!! No links please!!

laila [671]

Answer:

16(sin 30degrees) = BC

BC = 8

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2 years ago

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If csc theta = 8/7, which equation represents (cot theta) ?

Paul [167]

Out of the given choice, the equation represents $\cot \theta=\frac{\sqrt{15}}{7}$ .

Answer: Option B

<u>Step-by-step explanation:</u>

We know, $\csc \theta=\frac{1}{\sin \theta}$

$\sin \theta=\frac{1}{\csc \theta}$

Given data:

$\csc \theta=\frac{8}{7}$

So, now sin theta can express as

$\sin \theta=\frac{7(\text { opposite })}{8(\text { Hypotenuse })}$

Sin theta defined by the ratio of opposite to the hypotenuse. In general, the adjacent can be calculated by,

$\text {(opposite) }^{2}+(\text { adjacent })^{2}=(\text {Hypotenuse})^{2}$

$7^{2}+(\text { adjacent })^{2}=8^{2}$

$(\text {adjacent})^{2}=8^{2}-7^{2}=64-49=15$

Taking square root, we get

$\text { adjacent }=\sqrt{15}$

Also, we know the formula for cot theta,

$\cot \theta=\frac{1}{\tan \theta}=\frac{1}{\left(\frac{\sin \theta}{\cos \theta}\right)}=\frac{\cos \theta}{\sin \theta}$

Cos theta denoted as the ratio of adjacent to the hypotenuse.

$\cos \theta=\frac{\sqrt{15}(\text {Adjacent})}{8(\text {Hypotenuse})}$

Therefore, find now as below,

$\cot \theta=\frac{\left(\frac{\sqrt{15}}{8}\right)}{\left(\frac{7}{8}\right)}=\frac{\sqrt{15}}{8} \times \frac{8}{7}=\frac{\sqrt{15}}{7}$

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2 years ago

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A rectangular lawn measuring 8m by 4m is surrounded by a flower bed of uniform width.

Verdich [7]

I think its 32 meeters

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2 years ago

Which are the factors of x^2-4x-5

EleoNora [17]

$x^2-4x-5 =\\\\x^2+x-5x-5=\\\\x(x+1)-5(x+1)=\\\\(x-5)(x+1)$

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