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Jet001 [13]
3 years ago
14

What’s the correct answer ?

Mathematics
1 answer:
Leona [35]3 years ago
7 0
The answer is a) 35


The steps:
180° - 95 ° = 85 °
180 ° - (85 ° + 60 °)=35 °
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<img src="https://tex.z-dn.net/?f=9x-3%20%5Cleqslant%2011x%20-%203" id="TexFormula1" title="9x-3 \leqslant 11x - 3" alt="9x-3 \l
AURORKA [14]

Answer:

0 ≤x

Step-by-step explanation:

9x-3 ≤11x-3

Subtract 9x from each side

9x-9x-3 ≤11x-9x-3

-3 ≤2x-3

Add 3 to each side

-3+3 ≤2x

0 ≤2x

Divide by 2

0/2 ≤2x/2

0 ≤x

6 0
3 years ago
Which function is best represented by this graph ​
zavuch27 [327]

Answer:the potato is ugly

Step-by-step explanation:because it has marks

8 0
3 years ago
Suppose you go shopping for a new futon bed for your apartment/home. The model you really like happens to be on sale for $500. I
rodikova [14]
The answer will be 60 percent
8 0
3 years ago
How do i do this? i’m having trouble
Fantom [35]

Answer:

121

Step-by-step explanation:

5x-54=3x+16

5x-3x=16+54

2x=70

x=35

-------

mAB= 5x-54= 5*35-54= 175-54= 121

6 0
3 years ago
The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0
3 years ago
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