If lines are paralel, then they have the same slope
if the lines are pependicuilar, the slopes mutiply to -1
so
y=mx+b
m=slope
and
ax+by=c
-a/b is the slope
given
y=2/3x-2
slope is 2/3
x+y=4
slope is -1/1 or -1
2/3≠-1 and -1 times 2/3≠-1 so they are neither perpendicular or paralell
since they aren't paralell, we know they intersect somewhere
You stick the number of x into the function to produce the answer so
x=-8, y=-4
x=-4, y=-3
x=0, y=-2
x=4,y=-1
x=8,y=0
Answer: Fourth option: y^2=9^2+19^2-2(9)(19) cos(41°)
The law of cosines to solve for one side is:
c^2=a^2+b^2-2ab cos C
We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)
In this case c=y, a=9, b=19, and C=41°, then:
y^2=9^2+19^2-2(9)(19) cos (41°)
The correct answer is 12.25
Answer:
15%
Step-by-step explanation:
