The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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Answer is 5^12 which is choice A (assuming you meant to put the ^ symbol)
The bases are the same (both are 5), so you add the exponents: 4+8 = 12. The base stays the same the entire time.
So, 5^4*5^8 = 5^(4+8) = 5^12
(x,y,z)=(-4,-2,-5)
I added some images for explanation
Number 5) A hill that rises 2 feet for every 10 feet of run. Because a longer run is not as steep as a short run.
Number 6) They all are parallel, they do not intersect.
