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BARSIC [14]
3 years ago
8

Please help me i need help

Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0

Answer:

-3

Step-by-step explanation:

Cube root of (-27) ...we find a number that multiplies itself 3 times...its most likely to be a negative

Hence (-3)^3 = -27

viva [34]3 years ago
3 0

Answer:

the answer u are looking for is negative 3

Step-by-step explanation:

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What percent of the muffins were carrots
Readme [11.4K]

Answer:

0%

Step-by-step explanation:

Muffins aren't carrots, unless they are carrot muffins.

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3 years ago
Pls help .....30 points
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Answer:

id-2614656691

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3 years ago
What is the prime factorization of 28? Please Help! This is due tomorrow! I really want to get an A! Help, please!!!!!!!!!!!!
vovangra [49]
The answer is 2•2•7
Hope this helps
4 0
3 years ago
How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi
ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
Consider the system of equations.
Xelga [282]

Answer:

D and C

Step-by-step explanation:

Given the 2 equations

3x - y = 5 → (1)

2x + 3y = - 15 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate the y- term

9x - 3y = 15 → (3)

Add (2) and (3) term by term to eliminate y

11x + 0 = 0

11x = 0 ⇒ x = 0

Substitute x = 0 into either of the 2 equations and solve for y

Substituting into (2)

2(0) + 3y = - 15

0 + 3y = - 15

3y = - 15 ( divide both sides by 3 )

y = - 5

solution is (0, - 5 )

3 0
3 years ago
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