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3 years ago

What is the area of a circle with 11m and 9m?

Mathematics

1 answer:

Naya [18.7K]3 years ago

3 0

Answer:

99m

Step-by-step explanation:

multiply the two numbers

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In a Monopoly market, a firm is a price maker since there are no close substitutes to the product. You are asked to find the com

rewona [7]

ATC= TC/ Q
Avc= vc/q
Afc= Fc/ q
Mc= Change TC/ change q
Tc= vc+ fc
Vc= tc/ fc
Mr= change tr/ change q
P≠ mr

3 0

3 years ago

Benny is trying to learn how to ride a bike, but is terrified of falling. He did some research, and discovered that if he rides

Anestetic [448]

Answer:

a) 7.14% probability that Benny was learning to ride a bike using the training wheels

b) 28% probability that Benny was learning to ride a bike using the training wheels

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

Benny came home crying with a bruise on his knee, after falling. His mom is trying to guess how Benny was trying to learn to ride a bike.

a) Assuming that the probability that Benny was using each of these 3 methods is equal, what is the probability that Benny was learning to ride a bike using the training wheels?

Event A: Benny fell

Event B: Benny was using training wheels.

The probability that Benny was using each of these 3 methods is equal

This means that $P(B) = \frac{1}{3}$

He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;

This means that $P(A|B) = 0.1$

Probability of falling:

1/3 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.

1/3 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5

1/3 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then

$P(A) = \frac{0.1 + 0.5 + 0.8}{3} = 0.4667$

$P(B|A) = \frac{\frac{1}{3}*0.1}{0.4667} = 0.0714$

7.14% probability that Benny was learning to ride a bike using the training wheels

b) Since Benny's mom knows Benny so well, she knows that the probability that he was using training wheels is 0.7, regular bike is 0.2, and unicycle is 0.1. What is the probability now that Benny fell while using the training wheels?

Similar as above, just some probabilities change.

Event A: Benny fell

Event B: Benny was using training wheels.

The probability that he was using training wheels is 0.7

This means that $P(B) = 0.7$

He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;

This means that $P(A|B) = 0.1$

Probability of falling:

0.7 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.

0.2 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5

0.1 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then

$P(A) = 0.7*0.1 + 0.2*0.5 + 0.1*0.8 = 0.25$

$P(B|A) = \frac{0.7*0.1}{0.25} = 0.28$

28% probability that Benny was learning to ride a bike using the training wheels

7 0

3 years ago

Factor the polynomial: 1–bx–x+b

mylen [45]

Answer:

$1-bx-x+b$

Step-by-step explanation:

This can't be factored with rational numbers.

6 0

2 years ago

Read 2 more answers

Based on context clues, which of these words represents the best definition for the underlined word?

kondaur [170]

Answer:

Step-by-step explanation:

8 0

2 years ago

A machine at a bottling company fills water bottles. the number of bottles filled is proportional to the amount of time the mach

Whitepunk [10]

In the table shown below:

Let N be the number of bottles filled,

Let T be the time in hours.

Given that the number of bottles filled is proportional to the amount of time the machine runs, we have

$\begin{gathered} N\propto T \\ \text{Introducing a proportionality constant, we have } \\ N\text{ = kT} \\ \Rightarrow k\text{ = }\frac{N}{T} \\ \end{gathered}$

Let's evaluate the value of k for each day.

Thus, on monday,

$\begin{gathered} N\text{ = 9900} \\ T\text{ = 5.5} \\ \text{thus,} \\ k\text{ = }\frac{9900}{5.5} \\ \Rightarrow k\text{ = 1800} \end{gathered}$

Tuesday:

$\begin{gathered} N\text{ = }11160 \\ T\text{ = }6.2 \\ \text{thus,} \\ k\text{ = }\frac{11160}{6.2} \\ \Rightarrow k\text{ = 1800} \end{gathered}$

Wednesday:

$\begin{gathered} N\text{ = }12330 \\ T\text{ = }6.25 \\ \text{thus,} \\ k\text{ = }\frac{12330}{6.25} \\ \Rightarrow k\text{ = 1972.8} \end{gathered}$

Thursday:

$\begin{gathered} N\text{ = }10440 \\ T\text{ = }5.80 \\ \text{thus,} \\ k\text{ = }\frac{10440}{5.8} \\ \Rightarrow k=1800 \end{gathered}$

It is observed that all exept wednesday have the same value of k.

Thus, the amount of time required for the number of bottles filled on wednesday is evaluated as

$\begin{gathered} N\text{ = }12330 \\ k\text{ = 1800} \\ T\text{ = ?} \\ \text{but} \\ k\text{ = }\frac{N}{T} \\ 1800\text{ = }\frac{12330}{T} \\ \Rightarrow T\text{ = }\frac{\text{12330}}{1800} \\ T\text{ = 6.85} \end{gathered}$

Hence, the incorrect day is Wednesday. The amount of time for that many bottles should be 6.85 hours.

3 0

1 year ago