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2 years ago

I NEED THIS NOW!!

Mathematics

2 answers:

Airida [17]2 years ago

8 0

Answer:

a) x = 6° b) m∠B = 50°

Explanation:

(a) total angle measure of a triangle is 180°

8x + 2 + 70° + 60° = 180°

8x + 132° = 180°

8x = 180° - 132°

8x = 48°

x = 6°

(b)

m∠B = 8x + 2

m∠B = 8(6) + 2°

m∠B = 48° + 2°

m∠B = 50°

Elis [28]2 years ago

7 0

Answer:

A. X is 6 and B. Angle is 50

Step-by-step explanation:

PART A

Triangle sum theorem explains that all angles in a triangle add up to 180

(8x + 2) + 70 + 60 = 180

8x= 180-70-60-2

8x= 48

X= 48/8 =6

PART B

Using the formula provided, replace the x with 6

So it'll be 8(6)+2 = 48+2 = 50

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3 years ago

Consider the function f(x) = x^3 - 7x^2 - 2x + 14

mars1129 [50]

Answer:

There are 3 zeros, which are:

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Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14$

To get the zeros of $f(x)$ , set $y$ or $f(x) =0$

$0=x^3-7x^2-2x+14$

$x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)$

$\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0$

Using the zero factor principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0$

solving

$x-7=0$

$x=7$

$x+\sqrt{2}=0$

$x=-\sqrt{2}$

$x-\sqrt{2}=0$

$x=\sqrt{2}$

Therefore, there are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

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2 years ago

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Mama L [17]

Answer:

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