So there are three variables, rs2 label x, rs5 label y, rs10 label z
Lets write equeations using these variables.
x+y+z=120 (<span>A bag has a total of 120 notes)
2x+5y+10z=760 (total value)
2x+5*2y+10z=960 (twice as many rs5)
3 variables, 3 independent equations will give solution. There are a fair few ways to solve this. </span>
Answer:
1) 15a - 15c + 3
2) -7n + 31 + 13m + 7p or 13m - 7n + 7p + 31
3) 44x + 6y + 3
4) 9m - 6n + 23
Step-by-step explanation:
1. Add like terms. 6a + 9a=15a. -8c - 7c=-15c
2. Add like terms. You can rearrange them in descending order based off of exponents and variables.
3. Multiply what's in parentheses first (distribute the 6). It should end up being (6y + 42x). Then you add like terms and put in descending order.
4. Distribute the (-3) to what in the parentheses. It should end up being (-6n + 15 - 3m). Then you add like terms and put the expression in descending order.
Answer:
28.12
Step-by-step explanation:
Answer:
Step-by-step explanation:
Which Method Should Be Used to Solve a Quadratic Equation? Quadratic equations are of the form ax2 + bx + c = 0 where a, b and c are real numbers, a ≠ 0. Quadratic equations have two solutions, but it is possible that one solution may repeat. happy to help
Answer:
If it counts as a question, lol sure, I'd love to help
