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Kipish [7]
2 years ago
12

Which of the following expressions are equivalent to (9 7/8 + 2 4/5)-1/2

Mathematics
2 answers:
nikklg [1K]2 years ago
7 0

Answer:A and B. Step-by-step explanation: C) 9 7/8 - (- 2 4/5) - (- 1/2) = = 9 7/8 + 2 4/5 + 1/2 (F). D) - (- 9 7/8 + 2 4/5) - 1/2) =.

I hope this helped^.^

May i have brainliest? ^.^

Have a great day buddy! ~hailey

ludmilkaskok [199]2 years ago
3 0

Answer:

A and B both represent the expression (9 7/8 + 2 4/5) -1/2)

Step-by-step explanation:

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7 0
3 years ago
A coach is assessing the correlation between the number of hours spent practicing and the average number of points scored in a g
cricket20 [7]

Answer:

a) r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

b) m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

c) For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

Step-by-step explanation:

We have the following data:

Number of hours spent practicing (x) 0 0.5 1 1.5 2 2.5 3 3.5 4

Score in the game (y) 5 8 11 14 17 20 23 26 29

Part a

The correlation coefficient is given:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=9 \sum x = 18, \sum y = 153, \sum xy = 396, \sum x^2 =51, \sum y^2 =3141  

r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=51-\frac{18^2}{9}=15  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=396-\frac{18*153}{9}=90  

And the slope would be:  

m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

Part c

For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

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3 years ago
42 less than the product of 28 and an unknown number is 154
zalisa [80]
First you write out your equation, which is 28x-42=154. Then you solve you equation. First, add 42 to each side, get 28x=196. Divide both sides by 28, get x=7.
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Underline the ones that are the same. 5, 5, .50
KATRIN_1 [288]

Answer:

.5 and 5

Step-by-step explanation:

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2 years ago
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In JKL and PQR, if JK = PQ, congruent to PQR.<br><br> True or False
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Answer:

True

Step-by-step explanation:

Two shapes are congruent if when turning, flipping or sliding one shape it can become another.

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