I think it’s 25....Yeah I’m pretty sure it’s 25
- 4 1/5 = -21/5 = -42/10
-13 1/10 = -131/10
-42/10 - -131/10=
-42/10 + 131/10 = 89/10 = 8 9/10
answer is A
The formula
in solving the integral of the infinity of 3 is ∫3<span>∞?</span>(1<span>)÷((</span>x−2<span><span>)<span><span>(3/</span><span>2)</span></span></span>)</span><span>dx</span>
Substitute the numbers given
then solve
limn→inf∫3n(1/((n−2)(3/2))dn
limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)
=0+2=2
Solve for the integral of 2 when 2 is approximate to 0.
Transpose 2 from the other side to make it -2
∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C
(x−2)−1/2=1x−2−−−−√
0−(3−2)−1/2−1/2=2
<span> </span>
Given that x=number of days
To model the expressions we use the exponential growth given by:
y=a(b)^nx
where:
a=initial value
b=growth factor
n=24 hours
thus Colby's experiment will be:
y=50(2)^(1/2*24*x)
y=50(2)^(12x)
N/B we multiply by 24 so as to convert days into hours
b] <span>Jaquan's starts with 80 bacteria that double every 3 hours.
a=80, b=2
thus
y=80(2)^(1/3</span>×24×x<span>)
simplifying the above we get:
y=80(2)^(8x)</span>
