Multiply moles by molar mass
9.83 g age
The answer should be D. Hope this helps!!
<u>Given:</u>
# Molecules of NaOH = 1.50 * 10²³
<u>To determine:</u>
The # moles of NaOH present in the given molecules
<u>Explanation:</u>
By definition:
1 mole of NaOH corresponds to Avogadro's number i.e. 6.023*10²³ molecules
Therefore the moles of NaOH corresponding to the given molecules would be = 1.50*10²³ molecules NaOH * 1 mole NaOH/6.023*10²³ molecules NaOH
= 0.249 moles
Ans: 0.249 moles of NaOH
Atomic mass of Potassium = Mass of 1 atom of Potassium = 39.1 amu
Then
Mass of 6.02 x 1023 atoms of potassium = 39.1 x 6.02 x 1023 amu
=
We already know that
1 mole = 6.02 x 1023 atoms
Also
Number of mole = mass in grams/ atomic mass
Then
Mass in gram = Number of mole x atomic mass
= (39.1 x 6.02 x 1023)/(6.02 x 1023)
= 39.1 g
The correct option among all the options that are given in the question is the third option or option "B".
Answer:
-1215.9J is the work done
Explanation:
It is possible to find work done in the change of volume of a gas at constant pressure using:
W = -P×ΔV
<em>Where W is work, P is pressure and V is change in volume}</em>
Replacing:
W = -6atm×(5L-3L)
W = -12atmL
As 1atmL = 101,325J, work done in joules is:
-12atmL ×(101.325J / atmL) = <em>-1215.9J is the work done</em>
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