All categories

3 years ago

Which of the following best describes a metathesis reaction?

Chemistry

1 answer:

densk [106]3 years ago

4 0

Answer:

Explanation:

A metathesis reaction is a reaction in which cations and anions change partners.

A general equation for a metathesis is

AX+CY→AY+CX, where A and C are cations, and X and Y are anions.

There are three possible products of a metathesis reaction.

A. an insoluble (solid) precipitate

B. water (from neutralization reaction)

C. an insoluble gas that bubbles out of solution

Metathesis reactions are also called double replacement reactions and double displacement reactions.

You might be interested in

Q.1 What is one joule work ?

Irina-Kira [14]

Answer:

See below.

Explanation:

It is equal to the energy transferred to (or work done on) an object when a force of one newton acts on that object in the direction of the force's.

Best Regards!

8 0

3 years ago

Read 2 more answers

Convert 5 micrometers to meters.

k0ka [10]

Answer:

5e-6

Explanation:

7 0

3 years ago

Read 2 more answers

The chemical combination of the atoms of two or more elements is known as a/an

ehidna [41]

I believe it would be a compound

7 0

3 years ago

Write an expression for the equilibrium constant of each chemical equation: a. SbCl5(g)SbCl5(g) + Cl2(g) b. 2 BrNO(g)2 NO(g) + B

denis-greek [22]

Answer:

See explanation

Explanation:

Step 1: Data given

For the reaction aA + bB ⇆ cC + dD

Kc = [C]^c * [D]^d / [A]^a [B]^b

a. SbCl5(g) ⇄ SbCl3(g) + Cl2(g)

Kc = [Cl2]*[SbCl3] / [SbCl5]

b. 2 BrNO(g) ⇄ 2NO(g) + Br2(g)

Kc = [Br2]*[NO]² / [BrNO]²

c. CH4(g) + 2 H2S(g) ⇄ CS2(g) + 4 H2(g)

Kc = [H2]^41 * [CS2] / [H2S]²*[CH4]

d. 2CO(g) + O2(g) ⇄ 2CO2(g)

Kc = [CO2]² / [O2][CO]²

6 0

4 years ago

The rapid decomposition of sodium azide, NaN3, to its elements is one of the reactions used to inflate airbags: 2 NaN3 (s)  2 N

masha68 [24]

<u>Answer:</u> The amount of nitrogen gas produced is 3.864 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $NaN_3$ = 6.00 g

Molar mass of $NaN_3$ = 65 g/mol

Putting values in equation 1, we get:

$\text{Moles of }NaN_3=\frac{6.00g}{65g/mol}=0.092mol$

For the given chemical reaction:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

By Stoichiometry of the reaction:

2 moles of $NaN_3$ produces 3 moles of nitrogen gas

So, 0.092 moles of $NaN_3$ will produce = $\frac{3}{2}\times 0.092=0.138mol$ of nitrogen gas

Now, calculating the mass of nitrogen gas by using equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.138 moles

Putting values in equation 1, we get:

$0.138mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.138mol\times 28g/mol)=3.864g$

Hence, the amount of nitrogen gas produced is 3.864 grams

7 0

3 years ago