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Colt1911 [192]
3 years ago
7

Consider the reaction between iron (III) oxide, Fe2O3 and carbon monoxide, CO. Fe2O3 + 3CO --> 2Fe + 3CO2 In the process, 213

g of Fe2O3 are reacted with 140 of CO. (a) calculate mass of Fe formed (b) how many moles of the excess reagent is left at the end of the reaction? Pls show me how to calculate this using dimensional analysis :(
Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
8 0
To calculate the mass of Fe formed in a) we get first the limiting reactant between Fe2O3 and CO. Given the masses, the ratio of Fe2O3 is 1.33 while that of CO is 1.67. Hence the limiting reagent is Fe2O3. The mass of Fe formed is 148.98 grams. In b, the needed CO is only 112.04 grams. Hence, the excess is 27. 96 grams. 
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What is the volume, in liters, of 0.500 mol of c3 h8 gas at stp?
saw5 [17]
It's about .0934 Liters at STP. 
5 0
3 years ago
Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of
Neko [114]

Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)          

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

\eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles

Finally, the mass of SiH₄ is:

m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!    

3 0
3 years ago
How many protons does hydrogen have?
Nataly_w [17]

Hello there!

Hydrogen has one proton because the number of protons in an atom is equal to the atomic number of the element. S ince hydrogen's atomic number is 1, it has one proton.

I hope that's help !

4 0
3 years ago
Determine how many liters of hydrogen adjusted to STP there are in a 50.0 liter steel cylinder if the pressure inside is 100.0 a
Dvinal [7]

Answer : The volume of hydrogen gas at STP is 4550 L.

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 100.0 atm

P_2 = final pressure of gas at STP = 1 atm

V_1 = initial volume of gas = 50.0 L

V_2 = final volume of gas at STP = ?

T_1 = initial temperature of gas = 27.0^oC=273+27.0=300K

T_2 = final temperature of gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{100.0atm\times 50.0L}{300K}=\frac{1atm\times V_2}{273K}

V_2=4550L

Therefore, the volume of hydrogen gas at STP is 4550 L.

3 0
3 years ago
If the equation CO(g) + 2H2(g) →← → ← CH3OH(g) + energy is for a system at equilibrium, increasing the temperature will cause __
Eddi Din [679]

Answer:

[CH₃OH] to decrease and [CO] to increase.

Explanation:

  • Since the energy appears as a product. So, the system is exothermic that releases heat.
  • Increasing the temperature of the system will cause the system to be shifted to the left side to attain the equilibrium again.
  • So, the right answer is:

<em>[CH₃OH] to decrease and [CO] to increase.</em>

<em></em>

6 0
3 years ago
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