Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Answer:
Step-by-step explanation:
- x − (5 − 3x) ≤ 2x − 1
- x - 5 + 3x ≤ 2x - 1
- 4x - 5 ≤ 2x - 1
- 4x - 2x ≤ 5 - 1
- 2x ≤ 4
- x ≤ 2 or x ∈ (- oo, 2]
The graph includes all point to the left from point 2, same point included
It is 2 4/5, 2 4/5 is 2.8, 4/5 is greater than 3/4
Answer:
x = 17
Step-by-step explanation:
The two angles with measures form a linear pair and are supplementary.
The measures of supplementary angles has a sum of 180°.
If you add the two given measures, the sum must equal 180°.
4x + 2 + 110 = 180
4x + 112 = 180
4x = 68
x = 68/4
x = 17
