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goldfiish [28.3K]
2 years ago
14

PLsSsSs HELPpPPPp THIS IS SO CONFUSING!!!!

Mathematics
2 answers:
Sonbull [250]2 years ago
7 0

Answer:

ME NO SPEAK ENGLISH

Step-by-step explanation:

levacccp [35]2 years ago
7 0
The answer is 16
Because C=16π=2πr so you just divide 16 π by 2 π
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A line has a slope of 5 and y-intercept of -2. What is its equation in slope-intercept from? Write your answer using interfere,
olya-2409 [2.1K]

Answer:

y=5x-2

Step-by-step explanation:

8 0
3 years ago
Someone help worth 5 points :( help?
Tcecarenko [31]

Answer:

29

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A rectangular prism with length 12 m , width 8 m & height 15 m , find its surface area .
Irina-Kira [14]

Answer: 792\ m^2

Step-by-step explanation:

Given

The length of the rectangular prism is l=12\ m

width of the rectangular prism is w=8\ m

height of the rectangular prism is h=15\ m

The surface area of the rectangular prism is 2[wl+lh+hw]

Put the values

\Rightarrow 2[8\times 12+15\times 12+15\times 8]\\\Rightarrow 2[96+180+120]=2\times 396\\\Rightarrow 792\ m^2

The surface area of the rectangular prism is 792\ m^2

7 0
3 years ago
In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,
steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So P(B) = 0.20

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So P(A/B) = 0.06

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So P(B) = 0.30

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So P(A/B) = 0.03

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So P(B) = 0.50

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So P(A/B) = 0.02

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226

32.26% probability it was manufactured by machine C.

6 0
3 years ago
When you have your final draft, you are ready to_________your essay using the work processor.
uysha [10]

Answer:

C) Revise

Step-by-step explanation:

A final draft needs to be revised before it can be published

7 0
2 years ago
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