The answer is all of the because
Nestled at the edge of the arid Great Basin and the snowy Sierra Nevada mountains in California, Mono Lake is an ancient saline lake that covers over 70 square miles and supports a unique and productive ecosystem. The lake has no fish; instead it is home to trillions of brine shrimp and alkali flies. Freshwater streams feed Mono Lake, supporting lush riparian forests of cottonwood and willow along their banks. Along the lakeshore, scenic limestone formations known as tufa towers rise from the water's surface. Millions of migratory birds visit the lake each year.
From 1941 until 1990, the Los Angeles Department of Water and Power (DWP) diverted excessive amounts of water from Mono Basin streams. Mono Lake dropped 45 vertical feet, lost half its volume, and doubled in salinity.
The Mono Lake Committee, founded in 1978, led the fight to save the lake with cooperative solutions. We continue our protection, restoration, and education efforts today with the support of 16,000 members --and we host this Website.
In 1994, after over a decade of litigation, the California State Water Resources Control Board ordered DWP to allow Mono Lake to rise to a healthy level of 6,392 feet above sea level--twenty feet above its historic low. It is rising toward that goal -- click here for the current lake level, or visit one of the other links on this page for more of the Mono Lake story.
I would help but I can barely see the page
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
