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AveGali [126]
2 years ago
15

A tortoise is walking in the desert. It walks for 2 minutes at a speed of 5.12 meters per minute. For how many meters does it wa

lk?
Mathematics
2 answers:
sleet_krkn [62]2 years ago
8 0

Answer:

10.24

Step-by-step explanation:

2 x 5.12
=10.24

Allushta [10]2 years ago
3 0

Answer:

5.12×2=10.24 meters per hour

Distance =time ×speed

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Is(5, 6)a solution to the inequality<br> y &lt; 2x + 4 ?
Diano4ka-milaya [45]

Answer:

yes

Step-by-step explanation:

y < 2x +4

6 < 2·5 +4

6 < 14

4 0
2 years ago
HELPPPPP!!!!!! ASAPPPPPP!!!!!! TIMEDDDD!!!!
padilas [110]

Answer:

C(2,5)

Step-by-step explanation:

2(2)+3(5)>12

4+15>12

19>12

x-y>1

2-5>1

3>1

6 0
2 years ago
Read 2 more answers
The student population at a middle school in June, 2020 was 1678. In September, 2021, the student population was 1463. What is t
HACTEHA [7]

Answer: -12.81% decrease

Step-by-step explanation:

1678-1463/1463 * 100 = -12.8128

6 0
2 years ago
A building is 200 feet long. The length of the building on a scale diagram is 2 feet 6 inches. What is the height of the buildin
mafiozo [28]

Answer:

200 feet to 2 ft 6 inches (or 30 inches)

Convert the 200 feet to inches

2400 inches.

2400 divided by 30 inches is

80 inches per feet

600 inches divided by 80 is

7.5 inches rounded up is 8 inches

the answer is 8 inches

Step-by-step explanation:

3 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
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