In a geometric sequence, the first term is 6, the sum of infinity is 60, what is the common ratio?

2 answers:

8 0

Hello,

$u_{1} =6\\

\sum_{i=0}^\infty\6*q^i=60=6* \dfrac{1}{1-q} \\

\dfrac{1}{1-q} =10\\
1-q= \dfrac{1}{10} \\
-q= -\dfrac{9}{10} \\
\boxed{q= \dfrac{9}{10} }
$

Evgesh-ka [11]3 years ago

7 0

The common ratio for this one should be -2 because it;s an infinite geometry

You might be interested in

Will award brainliest to correct answer!

Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

$\angle \: ABP = \frac{180 - 80}{2} = 50 \degree$

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

6 0

3 years ago

The difference of sample means of two populations is 108.7, and the standard deviation of the difference in sample means is 32.

charle [14.2K]

Answer: A. The difference of the two means is significant at the 68% confidence level, so the null hypothesis must be rejected.

Step-by-step explanation:

I just got it right on PLATO, so I know it’s 100% correct.

5 0

4 years ago