Ask question

Ask question

All categories

2 years ago

7

HELLPPPPP MEEEEEEEEEEE

1 answer:

katrin [286]2 years ago

6 0

B = (-4, -3)

C = (0, -3)

D = (0, -2)

E = (-4, -2)

You might be interested in

What is the value of z in the table?<br>6<br>7<br>8<br>9

topjm [15]

Answer:

8

$100 \times 0.08 = 8$

6 0

3 years ago

3 1/6 as a improper fraction

tiny-mole [99]

The answer would be 19/6.

7 0

3 years ago

Read 2 more answers

Please answer #3 and #4. Due today! Will mark brainliest for best answer! :)

goldenfox [79]

Answer: #3 is just 5 x 6 bc 1/4 goes into 1 1/2 6 times, and it takes 5 minutes, so 5 x 6, which is 30.

#4 is 45 words per minute for 4 minutes so 45 x 4 which is 180

Plaz marke brainlist!

3 0

3 years ago

Read 2 more answers

Circle G:(x-14)^2+(y+12)^2=49 and Circle H:(x-18)^2+(y-8)^2=196. Describe a complete series of transformation from Circle G to C

Free_Kalibri [48]

Step-by-step explanation:

The equation

(x - a)² + (y - b)² = r²

describes a circle of radius r, with center at the point (a, b).

G is a circle of radius 7 units, centered at the point (14, -12).

H is a circle if radius 14 units, centered at the point (18, 8).

3 0

3 years ago

Read 2 more answers

compare the right-hand and left-hand derivatives to show that the function is not differentiable at the point P. find all points

Softa [21]

$f(x)= \left \{ {{ \sqrt{x} } \atop {2x-1}} \right. 
\\
\\ f'(x)= \left \{ {{ \frac{1}{2\sqrt{x}} } \atop {2}} \right. 
\\
\\ f'(1)= \left \{ {{ \frac{1}{2}} \atop {2}} \right. 
\\
\\ f'(1^-) \neq f'(1^+)$

Therefore, the function is not differentiable at x = 1.

$f(x)= \sqrt{x} 
\\
\\f'(x)= \frac{1}{2 \sqrt{x} } 
\\
\\f'(0)=\frac{1}{2 \sqrt{0} } = \infty$

Therefore, the function is not differentiable at x = 0.

3 0

3 years ago