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LenKa [72]
2 years ago
7

5(y + ⅖) = -13 May i pleas get help

Mathematics
2 answers:
Elanso [62]2 years ago
8 0

Given :

\qquad  \sf \: { \dashrightarrow 5 \bigg(y +  \dfrac{2}{5}  \bigg) = -13}

⠀

To Find :

  • The value of y

⠀

Solution :

\qquad  \sf \: { \dashrightarrow 5 \bigg(y +  \dfrac{2}{5}  \bigg) = -13}

⠀

Using distributive property we get :

\qquad  \sf \: { \dashrightarrow 5 y +  \cancel 5 \times \dfrac{2}{ \cancel{5}}  = -13}

\qquad  \sf \: { \dashrightarrow 5 y +  2 = -13}

⠀

Adding (–2) from both sides :

\qquad  \sf \: { \dashrightarrow 5 y +  2  + (- 2) = -13  + (- 2)}

\qquad  \sf \: { \dashrightarrow 5 y   = -15}

⠀

Dividing 5 from both sides :

\qquad  \sf \: { \dashrightarrow  \dfrac{5y}{5}  =  \dfrac{ - 15}{5} }

\qquad  {\pmb {\bf{ \dashrightarrow y   = -3}}}

⠀

<u>Therefore, The value of y = (–3)</u>

Aneli [31]2 years ago
6 0

Given:

  • \sf 5 \bigg(y + \dfrac{2}{5} \bigg ) = -13

~

Solution:

\longrightarrow \sf 5 \bigg(y + \dfrac{2}{5} \bigg ) = -13

\longrightarrow \sf 5y + 2 =  - 13

\longrightarrow \sf 5y =  - 13 - 2

\longrightarrow \sf5y =  - 15

\longrightarrow \sf y =  \dfrac{ -  \cancel{15}}{ \cancel{5}}

\longrightarrow \sf y =  - 3

~

{ \underline{ \therefore{ \bf \pmb {The  \: Value \:  of  \: y  \: is \:  -3}}}}

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