To find if one is a function, you must see if the pattern is the same.
Domains (x) can not have two values
I forget what the y value is called, but there can be the same y- value for multiple x - values
A. is not a function, because its ordered pairs are all over the place, and the value 4 in the x - value has two values assigned - 0 and 3, which makes it invalid.
B. may be a linear function. Its ordered pairs aren't jumping all over the place.
Both the x and y go up one for one, so the function could be y = x + 3
C. isn't because the x - value 2 has two values. Again, that makes this invalid.
D. is invalid because there is two x - values for 2.
Therefore, the answer is B.
Answer: the correct option is
(D) The imaginary part is zero.
Step-by-step explanation: Given that neither a nor b are equal to zero.
We are to select the correct statement that accurately describes the following product :
We will be using the following formula :
From product (i), we get
![P\\\\=(a+bi)(a-bi)\\\\=a^2-(bi)^2\\\\=a^2-b^2i^2\\\\=a^2-b^2\times (-1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }i^2=-1]\\\\=a^2+b^2.](https://tex.z-dn.net/?f=P%5C%5C%5C%5C%3D%28a%2Bbi%29%28a-bi%29%5C%5C%5C%5C%3Da%5E2-%28bi%29%5E2%5C%5C%5C%5C%3Da%5E2-b%5E2i%5E2%5C%5C%5C%5C%3Da%5E2-b%5E2%5Ctimes%20%28-1%29~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7Bsince%20%7Di%5E2%3D-1%5D%5C%5C%5C%5C%3Da%5E2%2Bb%5E2.)
So, there is no imaginary part in the given product.
Thus, the correct option is
(D) The imaginary part is zero.
Answer:
y = 5.595090517 or approximately 5.6
Step-by-step explanation:
Tan47 = 6/y
y x Tan47/Tan47 = 6/Tan47
y = 5.595090517 or approximately 5.6
Answer: x < -1 or x ≥ 3
Step-by-step explanation:
First we will look at the left part. The circle is open (not "equal to), arrow is pointing to the left (showing "less than" in this case), and the value is on -1;
x < -1
Second, we will look at the right part. The circle is closed (showing "equal to"), the arrow is pointing to the right (showing "greater than" in this case). and the value is on 3;
x ≥ 3
Lastly, we will write the final compound inequality. In this case, we use the word "or" because the solution value is either less than -1 or greater than and equal to 3.
<em>Note: The word "and" is only used when the "arrows point towards each other" creating a segment, so to say. In this case, they "point away" so we use the word or.</em>
