$\bf \cfrac{60}{1+3+5}\implies \cfrac{20}{3}\implies 6\frac{2}{3}\qquad \qquad \qquad \stackrel{\stackrel{1\cdot \frac{20}{3}}{}}{\frac{20}{3}}~:~\stackrel{\stackrel{3\cdot \frac{20}{3}}{}}{20}~:~\stackrel{\stackrel{5\cdot \frac{20}{3}}{}}{\frac{100}{3}}$

7 0

3 years ago

Find the area of the sector of a circle with radius 2 inches formed by a central angle of 4.3 radians: (in square inches)

aleksandr82 [10.1K]

Answer:

8.6 in²

Step-by-step explanation:

The area of the entire circle is A = πr², or A = π(2 in)².

This corresponds to a central angle of 2π radians, or 6.28 radians.

The area of the sector described above is just a certain fraction of that:

4.3 rad

-------------- * Area of circle = 0.685(4 * 3.14) = 8.6 in²

6.28 rad

3 0

3 years ago

The width and the length of a rectangle are consecutive even integers. If the width is decreased by 3 inches, then the area of t

Radda [10]

37.......................................

7 0

3 years ago

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