2.) A. 32 cm
3.) D. 6.4
4.) B.) 7
5.) 22.75
6.) 3
I’ll show u a picture of how I solved everything. Ask any questions if needed.
Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
1/4 pound beef, b = $0.75
=》 6 pounds beef = (6)/ (1/4) × b
=》 6 pounds beef = 24 × $0.75 =$18.00
A,81 because if you try checking 81 will be the only composite number im in 6 grade.....
Answer: 44
Step-by-step explanation: 396/9 = 44