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2 years ago

Distributive property to expand the algebraic expression.

Mathematics

1 answer:

frozen [14]2 years ago

8 0

Answer:

Step-by-step explanation:

Distributive property: a(b + c) = (a*b) + (a*c)

15(0.5g + 1.2s) = 15*0.5g + 15*1.2s

= 7.5g + 18s

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The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

5 0

3 years ago

Solve for x ....... thanks !

Len [333]

If we can match teh bases we can solve
because if x=x and xᵃ=xᵇ, we can conclude that a=b

16=2⁴
32=2⁵
rememeber that $(x^m)^n=x^{mn}$

$16^{3x+2}=32^{-2x-7}$
$(2^4)^{3x+2}=(2^5)^{-2x-7}$
$2^{4(3x+2)}=2^{5(-2x-7)}$
2=2 so we conclude that 4(3x+2)=5(-2x-7)

4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22

8 0

2 years ago

Solve 3(-1)(10-5-2(3))

AleksAgata [21]

The answer should be 3 :)

8 0

3 years ago

Read 2 more answers

A kite is fllying 115 ft above the ground. The length of the string to the kite is 150 ft, measured from the ground. Find the an

Kitty [74]

Answer:

The answer is sin θ = 115/150