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Lynna [10]
3 years ago
11

Help pls no li is I'll give you briliantest pls help pls pls pls pls pls pls pls pls pls pls​

Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

40.5

I hope u get a good mark glll

Step-by-step explanation:

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What is the area of this quadrilateral?<br> 3 ft<br> 4 ft<br> 3 fty
ipn [44]

Answer:

D

Step-by-step explanation:

12 square feet

7 0
2 years ago
A miners' cage of mass 420 kg contains 3 miners of total mass 280 kg. The cage
svp [43]

Answer:

5817 Newtons.

Step-by-step explanation:

Total mass of the cage + the miners = 700 Kg which is a downward force of  700g N.

The net downward force = 700g - T where T is the tension (force) in the cable. The g = acceleration due to gravity = 9.81 m s-2.

We  calculate the  acceleration of the cage by using an equation of motion:

Distance = ut + 1/2 a t^2     where u = initial velocity , t = time and a = acceleration:

75 = 0(t) + 1/2 a (10^2)

50a =  75

a = 1.5 m s-2.

So using Newtons second law of motion

Force = mass * acceleration:

700*9.81 - T = 700 * 1.5

T = 700 * 9.81 - 700*1.5

= 5817 N.

8 0
3 years ago
Solve the equation <br> -13/4 -x= 1/2x -1
ale4655 [162]

Answer:

x = 2 or 1/4

Step-by-step explanation:

-13/4 -x= 1/2x -1

Collect like terms

-13/4+1=1/2x+x

Using LCM

(-13+4)/4=(1+2x²)/2x

9/4=(1+2x²)/2x

Cross multiply

9(2x)=4(1+2x²)

18x=4+8x²

Turn into quadratic and solve

8x²-18x+4

Using formulae method

-b±(√b²-4ac)/2a

Where a=8, b= -18 and c=4

(-(-18)±(√(-18)²-4(8)(4))/2(8)

(18±(√324-128))/16

(18±√196)/16

(18±14)/16

(18+14)/16 or (18-14)/16

32/16 or 4/16

2 or 1/4

4 0
3 years ago
Read 2 more answers
The area of 5 centimeters long and 4 centimeters wide
slega [8]
Area= length * width

Area= 5*4

Area= 20

I hope this helps!
~cupcake
3 0
3 years ago
Read 2 more answers
A cube with 40-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers t
Molodets [167]

Answer:

940.8 N

1254.4 N

Step-by-step explanation:

I would think the questions would be to calculate the forces at the top of the cube and at the sides. Thus:

On the top:

F = pressure * area

P = density * gravity * height

the height would be:

1m - 0.4m = 0.6m

replacing:

P = 1000 * 9.8 * 0.6 = 5880

A = (0.4) ^ 2 = 0.16

F = 5880 * 0.16

F = 940.8 N

On the sides:

dF = d * g * h * dA

dA = 0.4 * dh replacing

dF = 1000 * 9.8 * h * 0.4 * dh

dF = 3920 * h * dh

We integrate both sides and we have:

F = 3920 * (h ^ 2/2), h = 0.6 up to h = 1

F = (3920/2) * (1 ^ 2 - 0.6 ^ 2)

F = 1254.4 N

3 0
3 years ago
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