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rewona [7]
2 years ago
12

**NEED HELP ASAP WILL GIVE BRAINIEST TO FASTEST ANSWER IF CORRECT**

Mathematics
1 answer:
trapecia [35]2 years ago
8 0
D is the correct answer because it can be simplified
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2*4+3y=29
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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
10 POINTS PLEASE HELP
Llana [10]

Answer:

A company sells tents in two styles, shown below.

The sides and floor of each tent made of nylon.

For tunnel tent:

In a composite figure of tunnel tent :

There are two semi circle, half cylindrical shape and its base is made of Square.

Area of semi-circle is given by:

where r is the radius the circle.

Here, Diameter(d) = 8 feet

We know that: Diameter(d) = 2 r

then;

8 = 2r

⇒ r= 4 ft.

Area of square =

then;

Area of square =  square ft

Lateral surface area of cylinder =  where r is the radius and h is the height

Here, h = 8 ft

Lateral surface area of half cylinder =  square ft

Total Surface area of tunnel tent(S)=2(Area of semi-circle)+(Lateral surface area of half cylindrical)+(Area of square)

Substitute the given values we have;

square ft.

For Pup tent:

Each side of tent = 8 ft

In a figure of Pup tent:

There are 3 square shape and two triangle.

Area of square =

then;

Area of square =  square ft

Area of a triangle is given by:

Each side of a triangle is same.

This is an equilateral triangle, and its height is given by:

then;

Area of triangle = square ft.

Substitute the given values we have;

Total surface area of Pup tent(S')

=  square ft.

⇒S' > S

therefore, the tunnel tent require less nylon to manufacture.

<h2 /><h2>PLZ GIMME BRAINLIEST :)) !!!!!!</h2>

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