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weqwewe [10]
2 years ago
11

Suzie made the following observations while spending the weekend at her

Chemistry
1 answer:
fomenos2 years ago
8 0

Answer:

...

Explanation:

i lowkey dont know what to put, i just need my points srry;(

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In a longitudinal wave, the _________ is the distance from one compression to the next compression or from one rarefaction to th
Andreyy89
The me drained is it
4 0
4 years ago
Answer each of the following questions with increases, decreases, or does not change.
Nitella [24]

Answer:

a) increases

b) decreases

c) does not change

d) increases

Explanation:

The vapour pressure of a liquid is dependent on;

I) the magnitude of intermolecular forces

II) the temperature of the liquid

Hence, when any of these increases, the vapour pressure increases likewise.

Similarly, the boiling point of a liquid depends on the magnitude of intermolecular forces present because as intermolecular forces increases, more energy is required to break intermolecular bonds.

Lastly, increase in surface area of a liquid does not really affect it's vapour pressure.

7 0
3 years ago
2. A 10.0 g ice cube, initially at 0.0ºC, is melted in 100.0 g of water that was initially 20.0ºC. After the ice has melted, the
arlik [135]

Answer:

The heat lost  by the water  Q_{water}  = 3.8 KJ

The heat gain by ice  Q_{ice} = 228.76 J

The heat required to melt the ice Q_{melt} = 3340 J

Explanation:

Mass of ice cube m_{ice} = 10 gm

Initial temperature of ice cube T_{ice} = 0 °c

Mass of water m_{water} = 100 gm

Initial temperature of water T_{w} = 20 °c

Final temperature of mixture T_{f} = 10.93 °c

(a). Total heat lost by the water Q_{water}  =  m_{water} C_{w} ( T_{f} - T_{w} )

⇒ Q_{water}  = 100 × 4.184 (20 - 10.93)

⇒ Q_{water}  = 3.8 KJ

This is the heat lost  by the water.

(b). Heat gained by the ice cube Q_{ice} = m_{ice} C_{ice} (T_{f} - T_{ice}  )

⇒ Q_{ice} = 10 × 2.093 × ( 10.93 - 0)

⇒ Q_{ice} = 228.76 J

This is the heat gain by ice.

(C). Heat required to melt the ice Q_{melt} = m_{ice} × Latent Heat

⇒ Q_{melt} = 10 × 334

⇒ Q_{melt} = 3340 J

This is the heat required to melt the ice.

7 0
3 years ago
how many moles of gas does it take to occupy 120 liters at a pressure of 2.3 atmospheres and a temperature of 340 K?
dezoksy [38]
Data:

P (pressure) = 2.3 atm
V (volume) = 120 L
T (temperature) = 340 K
n (number of mols) = ?
R (Gas constant) = 0.082 (atm*L/mol*K)

Formula: 

p*V = n*R*T

Solving:
p*V = n*R*T
2.3*120 = n*0.082*340
276 = 27.88n
27.88n = 276
n = \frac{276}{27.88}
n = 9.89956...\to \boxed{\boxed{n\approx 9.90\:mols}}\end{array}}\qquad\quad\checkmark


7 0
4 years ago
Plesse help asap!!!​
Naily [24]

Answer:

4.4×10² cm³

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 68.3 mm

Height (h) = 0.120 m

Volume (V) =?

Next, we shall convert the diameter (i.e 68.3 mm) to cm.

This can be obtained as follow:

10 mm = 1 cm

Therefore

68.3 mm = 68.3 mm / 10 mm × 1 cm

68.3 mm = 6.83 cm

Therefore, the diameter 68.3 mm is equivalent 6.83 cm.

Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:

1 m = 100 cm

Therefore,

0.120 m = 0.120 m/ 1 m × 100 cm

0.120 m = 12 cm

Therefore, the height 0.120 m is equivalent 12 cm.

Next, we shall determine the radius of the cylinder. This can be obtained as follow:

Radius (r) is simply half of a diameter i.e

Radius (r) = Diameter (d) /2

r = d/2

Diameter (d) = 6.83 cm

Radius (r) =?

r = d/2

r = 6.83/2

r = 3.415 cm

Finally, we shall determine the volume of the cylinder as follow:

Radius (r) = 3.415 cm

Height (h) = 12 cm

Volume (V) =?

Pi (π) = 3.14

V = πr²h

V = 3.14 × (3.415) ² × 12

V = 440 cm³

V = 4.4×10² cm³

Therefore, the volume of the cylinder is 4.4×10² cm³

8 0
3 years ago
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