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Taya2010 [7]
2 years ago
8

Determine the offspring genotypes:​

Biology
1 answer:
sergiy2304 [10]2 years ago
3 0

Answer:

PP × pp = Pp, Pp, Pp, Pp

Pp × pp = Pp, pp, Pp, pp

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Glucose-6-phosphate dehydrogenase deficiency (G6PD) is inherited as an X-linked recessive gene 43) in humans. A woman whose fath
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Answer:

50% or 1/2. The result remains unchanged if the husband were to have G6PD.

Explanation:

For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.

Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype X^GX^g. A normal man will have the genotype X^GY. When the 2 marries:

X^GX^g   x   X^GY = X^GX^G (normal female), X^GY (normal male), X^GX^g (carrier female), X^gY (affected male)It thus means that 50% or 1/2 of their sons will be expected to have G6PD.

Now, assuming the husband has G6PD, the mating becomes:

X^GX^g   x   X^gY = X^GX^g (carrier female), X^GY (normal male),  X^gX^g (affected female), X^gY (affected male)50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.

3 0
3 years ago
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