Answer:
Step-by-step explanation:
From the information given,
Mark: 6,7,8,9,10
frequency:5,4,7,10,4
a) Range = highest mark - lowest mark
Range = 10 - 6 = 4
b) The number of students in the group is the sum of the frequency. Therefore,
Number of students = 5 + 4 + 7 + 10 + 4 = 30 students
c) Mean mark = (mark × frequency)/total frequency
[(6 × 5) + (7 × 4) + (8 × 7) + (9 × 10) + 10 × 4)]/ 30
Mean mark = (30 + 28 + 56 + 90 + 40)/30 = 244/30
Mean mark = 8.1
Distance swam in 5 minutes = 85.4 yards
Since, 1 min = 60 seconds and 1 yard = 0.91 meter
5 minutes = 
seconds
85.4 yards = 
meters
So, Distance swam in 300 seconds = 77.7 meters
Now, we will use unitary method to determine the distance swam in 70 seconds.
Distance swam in 1 second = 
= 0.26 meter
So, Distance swam in 70 seconds = 
= 18.2 meters
Therefore, the swimmer took 70 seconds to cover the distance of 18.2 meters.
It should be D: 35. 14 + 6 = 20. I just multiplied that by two, which equals 40. That means there are 2 sets of 14 and 2 sets of 6. Since there is 10 leftover, I divided both by 2. 7 + 3 = 10. 14 x 2 = 28 + 7 = 35
Answer:
74.5
Step-by-step explanation:
i did it on my calculator and it says it is 74.5.
