Please help!!! Will give brainly if correct!! 50 points

Mathematics

2 answers:

azamat3 years ago

8 0

The answer is b all you have to do is imput a value

luda_lava [24]3 years ago

7 0

I'm pretty sure it's the third choice

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Hey! Want to help me out here? It's due soon ;-;

AveGali [126]

Answer:

Step-by-step explanation: All the numbers have to be less than 7 but greater than -45

7 0

2 years ago

Read 2 more answers

-5/2 x 5/7 help me i bad at math

saw5 [17]

Answer:

Step-by-step explanation:

assuming that the X is a multiplication symbol and not a variable, because the multiplication symbol is * not x, 5*5/2*7=25/14=1 and 11/14

3 0

4 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,