The linear approximation to

centered at

is

What this means is that you can use the tangent line to

at

to get a decent approximation of

at some other value of

to within a certain degree of accuracy depending on how close this value

is close to

. (Note that when

, the approximation is exact;

.)
So what you're asked to do is find an approximate value of a zero of

near

. That is to say, you're looking for some value

such that

, but all you have at your disposal is the linear approximation to the function.



You know that if

is a zero of

, then

, so you get

Solving for

, you find

This means that an approximate zero of

is

.
The equation factors as
.. (x +3)(x +4) = 0
By the zero-product rule, the roots are
.. x1 = -4
.. x2 = -3
Answer:
A=46 degrees, B=33.4 degrees, C=100.6 degrees
a=34, b=27, c=48.2
Step-by-step explanation:
(a/sin(A)) = (b/sin(B)) = (c/sin(C))
we are given
(34/sin(46)) = (27/sin(B))
34sin(B) = 26sin(46)
34sin(B) = 18.702834809
sin(B) = 0.550083377
note use inverse sin function to find angle B
B = 33.372733167 approx 33.4 degrees then
C = 180 - (46 + 33.4) = 100.6
Then, (b/sin(B)) = (c/sin(C))
27/0.550083377 = c/0.982935349
0.550083377 * c = 27 * 0.982935349
0.550083377 * c = 26.539254427
c = 48.245876056 approx 48.2
.
Lastly, you get: A=46 degrees, B=33.4 degrees, C=100.6 degrees
a=34, b=27, c=48.2
Answer: the answer in c on edge
Step-by-step explanation:
Answer:
Is one of them supposed to by x?
Step-by-step explanation:
6x- y = 11
-4x + 5y = 8
With a system of equations, you need to solve for one variable first and the substitute to find the other variables. y is easier to solve for.
6x - y =11 Subtract 6x to both sides.
-y = -6x +11 Multiply by -1 on both sides
y = 6x - 11
We now subsitute y with 6x - 11 in the other equation.
-4x + 5y = 8
-4x + 5(6x-11) = 8
-4x +30x -55 =8
26x = 63
x = 63/26
and now we subsitute this to solve for actual y.
y= 6x -11
y= 6*(63/26)-11