Use law of cosines
o^2=p^2+q^2-2pqCos(C)
o^2=38^2+29^2-38*29Cos(39)
o^2=1444+841-1712.83
o^2=572.17
o=23.92
Say 24 cm
Answer:
0
Step-by-step explanation:
7c =
7(0) = 0
hope you understand
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
∠ABD = 32
Step-by-step explanation:
Since ∠ABC is the total angle, subtract ∠DBC from ∠ABC to get ∠ABD.
145 - 113 = 32