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motikmotik
3 years ago
5

Pie charts without the amount of things?

Mathematics
1 answer:
tangare [24]3 years ago
7 0
You can find total number of cars doing this:
72° - 8 cars
360° - X cars

X = (360 * 8) / 72

You follow the logic for the cars
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Convert 6 miles to meters​
Drupady [299]

Step-by-step explanation:

6miles= 9656.064 metres

5 0
2 years ago
Read 2 more answers
Which of these points lies on the circle with the center (2,3) and radius 2?
yan [13]

Answer:

The answer to your question is the letter A.

Step-by-step explanation:

Data

Center = (2, 3)

radius = 2

Process

1.- Find the equation of the line

              (x - h)² + (y - k)² = r²

-Substitution

              (x - 2)² + (y - 3)² = 2²  

-Simplification

              (x - 2)² + (y - 3)² = 4

-Evaluate the points in the equation

A. (4, 3)

              (4 - 2)² + (3 - 3)² = 4

                   2² + 0 = 4

                           4 = 4     This point lies in the circle

B (-1, 0)

              (-1 - 2)² + (0 - 3)² = 4

                        -3² + (-3)² = 4

                          9 + 9 = 4   This point is not part of the circle

C. (1, 3)

              (1 - 2)² + (3 - 3)² = 4

                 (-1)² + (0)² = 4

                            1 = 4          This point is not part of the circle

D. (3, 4)

              (3 - 2)² + (4 - 3)² = 4

                     1² + 1² = 4

                            2 = 4          This point is not part of the circle

5 0
3 years ago
Read 2 more answers
What is the answer to this question
astra-53 [7]

Answer: I think the answer is B

Step-by-step explanation:

8 0
3 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
2 years ago
Josh drew ∆ ABC with mm∠A = 40°, m∠B = 60° and m∠ C = 80°. Howard drew ∆ XYZ with m∠Y = 60° and m∠ Z = 80°. What can you say abo
aliya0001 [1]

Answer:

Both of these triangles are congruent.

Step-by-step explanation:

All 3 angle measures of both of the triangles are equivalent and correlate to each other. This makes the triangles congruent.

7 0
3 years ago
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