1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
11111nata11111 [884]
2 years ago
15

HELPPP plsssssss (apparently it’s not x<10 sooo)

Mathematics
1 answer:
gavmur [86]2 years ago
6 0

Answer:

5x+2<32

5x<30

x<30/5

x<6

You might be interested in
Leo multiplied all numbers from 1 to 11 and wrote the answer on the board. During the break three digits were erased 39,9...6,8.
Pavlova-9 [17]
11! = 39,916,800

The erased digits are 1, 0, 0.
6 0
3 years ago
There are 12 girls and 18 boys in a class. Teacher wants to form groups with the same
Stells [14]

Answer:

6 groups

2 girls, 3 boys

Step-by-step explanation:

To find the answer, first find the Greatest Common Factor or the GCF. The GCF in this case is 6. So, the amount of groups is 6. Then divide each number by 6, so there will be 2 girls in each group and 3 boys in each group.

8 0
3 years ago
8 x plus 2y equal 7?​
juin [17]

Answer:

8x+2y=68

If this doesn't answer your question, please comment so that I can help you.

4 0
3 years ago
Read 2 more answers
What is the common ratio for the geometric sequence?<br><br> 18, 12, 8, 16/3,…
alex41 [277]

Answer:

2/3

Step-by-step explanation:

Given : A geometric sequence : 18, 12, 8, 16/3,…

Solution :

Each term is found by multiplying the previous term by a constant in a Geometric Sequence .

In a Geometric Sequence  common ratio is denoted by r


r = \frac{a_{n} }{a_{n-1} }


for n = 2


r = \frac{a_{2} }{a_{1} }


⇒r = \frac{12 }{18 }


⇒r = \frac{2 }{3 }


for n = 3


r = \frac{a_{3} }{a_{2} }


⇒r = \frac{8 }{12 }


⇒r = \frac{4 }{6 }


⇒r = \frac{2}{3 }


Thus the common ratio 'r' = 2/3

6 0
3 years ago
Read 2 more answers
A gaming console cost $299.99. Each game that comes with the console is an additional cost of $20.00. Mr. Yao decide to by x num
givi [52]

This question is not correctly written

Complete Question

A gaming console cost $299.99. Each game that comes with the console is an additional cost of $20.00. Mr. Yao decide to by x number of games Write a variable expression for cost of the number of games Mr. Yao bought

Answer:

Variable expression for the cost of the number of games that Mr Yao bought =

$20x

Where x = number of games that he bought.

Step-by-step explanation:

A variable expression can be defined as a mathematical expression where there is at least one (or more) unknown variable(s)that we have to look or solve for.

The unknown variable is always represented by letters of the alphabet, a, b, x, y e.t.c.

A variable expression can also be called an algebraic expression.

From the above question, we are told that:

Cost of a gaming console = $299.99

If you buy a game with the console = Additional $20.00

My Yao bought = x number of games

Variable expression for the cost of the x number of games that Mr Yao bought

$20 × x

= $20x

Where x = number of games that Mr Yao bought.

4 0
3 years ago
Other questions:
  • What is 6743 divided by 4
    11·2 answers
  • Keisha, Miguel, and Pablo sent a total of 69 text messages during the weekend. Miguel sent 5 more messages than Keisha. Pablo se
    11·1 answer
  • 5 to the 2 power<br> help
    15·2 answers
  • Please help! This is algebra btw
    11·1 answer
  • Please help me please really need help please
    15·1 answer
  • I WILL GIVE BRAINLIST
    13·1 answer
  • Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
    5·1 answer
  • Which is an equation of the line that passes through the points (-1,9) and (4, 24)?
    11·1 answer
  • The area of a square is 50 square yards. What is the length, in yards, of one side of the square?
    8·1 answer
  • If a carton contains 6 eggs, how many eggs are there in 13 cartons?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!