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sineoko [7]
3 years ago
12

Which ordered pairs are solutions to the inequality y−2x≤−3?

Mathematics
2 answers:
My name is Ann [436]3 years ago
6 0

we will proceed to resolve each case to determine the solution

we have

y-2x \leq -3

y\leq2x-3

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

<u>case a)</u> (5,-3)

Substitute the value of x and y in the inequality

-3\leq2*5-3

-3\leq7 -------> is true

so

The ordered pair (5,-3) is a solution

<u>case b)</u> (0,-2)

Substitute the value of x and y in the inequality

-2\leq2*0-3

-2\leq-3 -------> is False

so

The ordered pair (0,-2) is not a solution

<u>case c)</u> (-6,-3)

Substitute the value of x and y in the inequality

-3\leq2*-6-3

-3\leq-15 -------> is False

so

The ordered pair(-6,-3) is not a solution

<u>case d)</u> (1,-1)

Substitute the value of x and y in the inequality

-1\leq2*1-3

-1\leq-1 -------> is True

so

The ordered pair (1,-1) is a solution

<u>case e)</u> (7,12)

Substitute the value of x and y in the inequality

12\leq2*7-3

12\leq11 -------> is False

so

The ordered pair (7,12) is not a solution

Verify

using a graphing tool

see the attached figure

the solution is the shaded  area below the line

The points A and D lies on the shaded area, therefore the ordered pairs A and D are solution of the inequality

sergeinik [125]3 years ago
3 0
The first and fourth one
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Lady_Fox [76]

Answer:

  • 0.008 °C

Explanation:

<u>1) Write the changes in the temperature of the city over the 4 days in an easy way to read.</u>

<u />

  • 1.34 °C
  • - 5 / 7 °C
  • - 0.75 °C
  • 4/9 ° C

<u />

<u>2) Write the expression to show the average daily change in temperature.</u>

The average of a set of data is calculated with the expression:

  • Average = (sum of the data) / amount of data

Hence, you need to add the four change of temperature data and divide by 4.

The expression is:

  • Average =  [ 1.34 °C + (- 5 / 7 °C) + ( - 0.75 °C) + 4/9 ° C ] / 4

<u>3) Write the steps to solve the expression:</u>

You can choose between adding  fractions or adding the decimal forms of the numbers.

If you choose adding decimals, keep the complete decimals in your calculator, to avoid the accumulation of errors due to rounding. Round only the final result.

These are the steps.

<u>a. Find the decimal forms of the fractions:</u>

  • - 5/7  ≈ 0.71428
  • 4 /9 ≈ 0.44444

<u>b. Add the four data:</u>

  • 1.34°C + (- 0.71428 °C) + (-0.75 °C) + 0.44444 °C ≈ 0.32019 °C

<u />

<u>c. Divide the sum by the number of data (4)</u>

  • 0.32019 °C / 4 ≈ 0.080004 °C

<u>4. Round to the nearest hundredth</u>

The place of the hundreth is the second after the decimal point, which is 8 in this case:

  • 0.080004 °C ≈ 0.08 °C

7 0
2 years ago
What is the value of the expression (x-y)2 when x=5 and y=-1
rodikova [14]
(5- -1)2
(5+1)2
6x2
12
6 0
3 years ago
Analyze the decimal number 8.46 and determine the value of each digit.
AURORKA [14]

Answer:

8 units, 4 tenths and 6 hundredths

Step-by-step explanation:

The decimal number 8.46 can be expressed as following

The number at unit place is 8

The number at tenth place is 4

The number at hundredth place is 6

6 0
2 years ago
Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school. What is the mean
ra1l [238]

Answer:

The mean of sampling distribution of the proportion of the students who prefer later start times for school

                        μₓ = p = 0.63

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given sample size 'n' =200

given data Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school

sample proportion

                        p = \frac{x}{n} = \frac{126}{200} = 0.63

The mean of sampling distribution of the proportion of the students who prefer later start times for school

                        μₓ = p = 0.63

Standard deviation of the proportion

                     S.D = \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.63(1-0.63)}{200} } = 0.034

5 0
3 years ago
Hurry hurry hurry hurry 50 points help plz help...it would be better if you have a picture..plz use steps
Ymorist [56]

Our goal here is to create a copy of line segment PQ, through various steps. Let's start with drawing line segment PQ, respectively point R a fixed distance away from the segment.

It would be wise to use a compass in this case, and a ruler for certain.

So we have this segment PQ, and point R a " fixed distance " away from PQ.

( 1. Extend a compass to match with the length of PQ,

( 2. Move this compass ( without changing it's length ) so that one endpoint matches with point R

( 3. Now draw an arc with this compass, where this line will be

( 4. Take your ruler and draw a straight line from this point R to your arc. It would be wise to draw this line to the middle of the arc you created.

If you like, take a look at the attachment below to see what it should look like.

I have done these questions before, so I can assure you that this experiment is proved correctly!

8 0
2 years ago
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