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andreev551 [17]
2 years ago
6

A rental car agency charges $160.00 per week plus $0.25 per mile to rent a car. How many miles can you travel in one week for $3

60.00?
The number of miles you can travel in one week for $360.00 is. (Type a whole number.)
I need the answer quick
Mathematics
1 answer:
Phoenix [80]2 years ago
4 0

Answer:

Step-by-step explanation:

M = miles

.25M + 160 = 360.00

.25  = 360 - 160

200/ .25

M = 800 miles

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What value of makes this equation true? sin(30) = cos()
masya89 [10]

Answer:

cos60°

Step-by-step explanation:

Using the cofunction identity

cos(90 - x) = sinx , then

sin30° = cos(90 - 30)° = cos60°

4 0
3 years ago
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Desde la parte más alta de un edificio a 25 m una persona lanza hacia la base un objeto de 150 g con una velocidad de 0.8 m por
ANTONII [103]

Answer:

E_{T} = 36.84 J        

Step-by-step explanation:

La energía mecánica total está dada por:

E_{T} = E_{c} + E_{p}

E_{T} = \frac{1}{2}mv^{2} + mgh

En donde:

m: es la masa = 150 g

v: es la velocidad = 0.8 m/s

h: es la altura = 25 m

g: es la gravedad = 9.81 m/s²

E_{T} = \frac{1}{2}mv^{2} + mgh = \frac{1}{2}0.15 kg*(0.8 m/s)^{2} + 0.15 kg*9.81 m/s^{2}*25 m = 36.84 J

Por lo tanto, la energía mecánica total es 36.84 J.

Espero que te sea de utilidad!      

5 0
3 years ago
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muminat

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3 years ago
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

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Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

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4 years ago
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