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2 years ago

Identify the mean of each distribution. Distribution A Mean = Distribution B Mean = Distribution C Mean =.

Mathematics

2 answers:

yan [13]2 years ago

7 0

Answer:

100

200

B,C,A

Step-by-step explanation:

100% edge 2022

mariarad [96]2 years ago

5 0

Answer:

100

200

B,C,A

Step-by-step explanation:

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Mr. Stanford’s greenhouse has the dimensions shown. The volume of the greenhouse is 90 cubic yards. Find the missing dimension o

bulgar [2K]

Answer:

$h=10\ yd$

Step-by-step explanation:

we know that

The volume of the triangular prism of the figure is equal to

$V=Bh$

where

B is the area of the triangular base

h is the height of the triangular prism

Find the value of B

$B=\frac{1}{2}(6)(3)=9\ yd^{2}$

we have that

$V=90\ yd^{3}$

substitute the values and solve for h

$90=9h$

$h=90/9=10\ yd$

5 0

3 years ago

How many solutions does the system of linear equations 6a + 3b = 12 and<br> 6a - 3b = 12 have?

Olin [163]

Answer:

One solution

Step-by-step explanation:

Lets solve it for b

3b= -6a+12

3b= 6a-12

Simplifying

b= -2a+4

b= 2a+4

Both have same slope and intercept hence both lines are going to intersect at one point. So the equations are having one solution.

3 0

3 years ago

Mathematics and fractions 1/2 and 6/12

77julia77 [94]

Answer:

Equivalent fractions

Step-by-step explanation:

7 0

3 years ago

A label is placed around the juice box below, not including the bases.

Nonamiya [84]

Answer:

so is it 28? i need help too

3 0

3 years ago

Let A = (1, 0, 3) and B = (−3, 2, 1).

Romashka-Z-Leto [24]

Answer:

a) $(-\frac{\sqrt{24}}{6} ,\frac{\sqrt{24}}{12} ,-\frac{\sqrt{24}}{12})$

b) $(-1,1,2)$

c) $-2x+y-z=1$

Step-by-step explanation:

AB, OB, OA are vectors.

$AB = OB - OA = (-3, 2, 1) - (1, 0, 3) = (-4, 2, -2)\\||AB|| = \sqrt{(-4)^2+2^2+(-2)^2}=\sqrt{24}\\$

Normalizing AB: $\frac{AB}{||AB||} = (\frac{-4}{\sqrt{24}},\frac{2}{\sqrt{24}}, \frac{-2}{\sqrt{24}})=(-\frac{\sqrt{24}}{6} ,\frac{\sqrt{24}}{12} ,-\frac{\sqrt{24}}{12})$

OM, OA, OB are vectors.

$OM = \frac{1}{2}OA+\frac{1}{2}OB=(\frac{-3+1}{2} ,\frac{2+0}{2}, \frac{1+3}{2} )=(-1,1,2)$

So, $M = (-1,1,2)$

$-4x+2y-2z=(-4)(-1)+(2)(1)+(-2)(2)=4+2-4=2$

Hence,

$-2x+y-z=1$

5 0

2 years ago