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2 years ago

Pls pls help quick pls help

Mathematics

1 answer:

Tanya [424]2 years ago

8 0

Answer:

a. 0.23=23%=23/100=twenty-three hundredths

b. 0.70=70%=7/10=seven tenths

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Line a is formed by using the points -1,6 and 3,-2 Line B is formed by using the point -3,0 and 5,4.What linear equations can be

emmasim [6.3K]

Answer:

y = -x + 5

y = x/2 + 3/2

Step-by-step explanation:

First we calculate the slope as difference between coordinates

a) P₁ ( -1 , 6 ) P₂ ( 3 , 2 )

m = Δy/Δx ⇒ m = ( y₂ - y₁ ) / ( x₂ - x₁ ) ⇒ m = (2 -6 ) / (3 -(-1))

m = -4 /4

m = -1

Now we have:

y - y₁ = m ( x - x₁ ) ⇒ y - 6 = (-1) ( x - (-1))

y - 6 = -1 * ( x + 1 ) ⇒ y - 6 = - x - 1

y = -x + 5

In the second case

Q₁ ( -3 , 0 ) Q₂ ( 5 , 4 )

Again we calculate the slope

m = Δy / Δx ⇒ m = ( 4 - 0 ) / ( 5 - (-3)) ⇒ m = 4 / 8 ⇒ m = 1/2

m = 1/2 or x = 0,5

And

y - y₁ = 1/2 ( x - x₁ ) ⇒ y - y₁ = 1/2 ( x - (-3)) ⇒ y - 0 = 1/2 * x + 3/2

y = x/2 + 3/2

6 0

3 years ago

What is the result ?

yuradex [85]

Answer:

5+0=5 5+1+0=6 56

4+2=6 3+4+2=9 69

2+1=3 6+2+1=39

Step-by-step explanation:

there are 2 ways

3 0

3 years ago

Read 2 more answers

What does x equal in this equation<br><br>1/4(x-16)=3/4(x+20)?<br>

erma4kov [3.2K]

Answer:

1/4x - 4 = 3/4x - 15

-1/2x - 4 = -15

-1/2x = -11

x = 22

6 0

3 years ago

Help?? PLSSSS NOWWWWW

Vesnalui [34]

Using the equation y=9x you can substitute x for the hours. Y=9 times 5 and y=9 times 8. Y=45 and y=72. The range is $45-$72

7 0

4 years ago

What is the area of the logo?

Ludmilka [50]

Answer:

$the \: area \: of \: the \: logo \: is \: {91cm}^{2}$

Step-by-step explanation:

To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.

Area of the square.

To calculate the area of the square you have to calculate the square of one of its sides, following the formula:

$a = {a}^{2}$

Where "a" is the length of one of its side.

The side length of the square is a=7cm, so its area will be:

$asquare = {7}^{2} \\ asquare = {49cm}^{2}$

Area of the triangles.

The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.

To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:

$a = \frac{b.h}{2} \\ a = \frac{7.4}{2} \\ a = \frac{28}{2} \\ a = {14cm}^{2}$

The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:

$atriangles = 3a \\ atriangles = {42cm}^{2}$

Now that the area of all shape are calculated, you have to add them to determine the area of the logo:

$alogo = asquare + atriangle \\ alogo = 49 + 42 \\ alogo = {91cm}^{2}$

4 0

3 years ago

Read 2 more answers