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STALIN [3.7K]
3 years ago
12

What is the mean and the median for 72 75 78 72 and 73

Mathematics
2 answers:
denpristay [2]3 years ago
7 0
Mean: 74
(72+72+73+75+78) divided by 5

median: 73
(line all the numbers up in numerical order then cross out one from each side and repeat process until in the middle)
mrs_skeptik [129]3 years ago
5 0
Mean= add up all the numbers and divide it by how many there
Median= the number in the middle

are
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HELP ME BEFORE I DIE!
KonstantinChe [14]

Answer:

0.6 or \frac{3}{5}

Step-by-step explanation:

Using the Pythagorean theorem (a^{2} +b^{2} =c^{2}) we get that the hypotenuse is 5.

so the cos V is adjacent over the hypotenuse. so if adjacent is 3 and hypotenuse is 5, the answer is \frac{3}{5} which equals 0.6 in decimal form.

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Alinara [238K]

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12 more than (-17) is<br><br> A. 29 B. -29 C. -2 D. -5
Ivanshal [37]
-5 because 12+-17 is -5
7 0
3 years ago
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At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
pav-90 [236]

Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
3 years ago
Part 2 to that question answer right pls
Marta_Voda [28]

Answer:

1. decreases

2. 31.50

Step-by-step explanation:

It decreases because there's a negative sign.

It's 31.50 because 10.50 * 3 = 31.50

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3 years ago
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