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2 years ago

Can someone give me the ans short ans

Mathematics

1 answer:

artcher [175]2 years ago

4 0

Step-by-step explanation:

please mark me as brainlist

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6p + 4 / 7 + 5p - 6 / 2 - 3p / 4 when p = 4

vesna_86 [32]

Step-by-step explanation:

Given p = 4,

substitute p= 4 into the expression

6p+4/7+5p-6/2-3p/4

$6(4) + \frac{4}{7} + 5(4) - \frac{6}{2} - \frac{3(4)}{4} \\ = 24 + \frac{4}{7} + 20 - 3 - 3 \\ = 44 + \frac{4}{7} - 3 - 3 \\ = 38 + \frac{4}{7} \\ = 38 \frac{4}{7}$

4 0

3 years ago

Anyone mind helping!?

katrin2010 [14]

Answer:

Step-by-step explanation:

-(x^2+4x-21)

If you were to factor this, it would be,

-(x+7)(x-3)

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6 0

2 years ago

Read 2 more answers

Danielle earns a 7.25% commission on everything she sells at the electronics store where she works. She also earns a base salary

Nikitich [7]

Answer:

Last week her sales were $4500.

Step-by-step explanation:

Given:

Danielle earns a 7.25% commission on everything she sells at the electronics store where she works.

She also earns a base salary of $750 per week.

Her total earnings for the week were $1,076.25.

Now, to find her sales last week.

Let the sales of last week be $x.$

Base salary = $750.

Total earnings = $1076.25.

So, we deduct the base salary from the total earnings first:

$1076.25-750$

$=326.25.$

Thus, the rest of the earnings is $326.25 which is the 7.25% commission on sales.

Now, to get the sales of last week we put an equation:

$7.25\%\ of\ x=326.25$

$\frac{7.25}{100} \times x=326.25$

$\frac{7.25x}{100} =326.25$

Multiplying both sides by 100 we get:

$7.25x=32625$

Dividing both sides by 7.25 we get:

$x=4500.$

The sales of last week = $4500.

Therefore, last week her sales were $4500.

7 0

3 years ago

Find the solution to dy/dt = 7 y satisfying y(9) = 5

AVprozaik [17]

$\rm \dfrac{dy}{dt}=7y,\qquad\qquad\qquad y(9)=5$

I'm not sure what methods you've learned up to this point but one option is to apply separation of variables:

$\rm \dfrac{dy}{y}=7dt$

and then integrate from there,

$\rm ln|y|=7t+c$

exponentiate to isolate y,

$\rm |y|=e^{7t+c}$

Apply exponent rule,

$\rm |y|=e^c e^{7t}$

rename this e^c as some new constant, perhaps A,

$\rm \pm y=A e^{7t}\qquad\qquad A>0$

This A can only be positive, non-zero, but absorbing the plus/minus fixes that restriction,

$\rm y=A e^{7t}\qquad\qquad A\ne0$

Use your initial information to solve for this unknown value A,

$\rm y(9)=A e^{7\cdot9}=5$

solving for A, dividing by the exponential,

$\rm A=5e^{-63}$

So we get a final result of

$\rm y(t)=5e^{-63}e^{7t}$

apply exponent rule again to get a better looking answer, and factor,

$\rm y(t)=5e^{7(t-9)}$

Lemme know if too confusing.

3 0

3 years ago

Someone please help I forgot how to do this

Flura [38]

Can u send a close up picture I can’t see it

4 0

3 years ago

Can someone give me the ans short ans​

Can someone give me the ans short ans